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slava [35]
3 years ago
7

Plz Help (Not really tho). Maath stuff.

Mathematics
2 answers:
Pani-rosa [81]3 years ago
7 0

Answer:

I don't know the answer

Rudik [331]3 years ago
3 0

Answer:

you cheater. i loved you...

Step-by-step explanation:

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Among all rectangles having a perimeter of 25m, find the dimensions of the one with the largest area​
Katen [24]

Answer:

Square with side length 25/4 m

Step-by-step explanation:

The area is always going to be largest for a rectangle when the two dimensions are equal.  You are looking for a square. What square has perimeter 25? 4s=25 so the side length of this rectangle (Square) is 25/4 m.

7 0
3 years ago
Read 2 more answers
Simplify (question is in the picture)
Sholpan [36]
Your answer is 26.9 so u could round it up to 27
3 0
3 years ago
Read 2 more answers
Lara planted some seeds. For every 3 seeds Lara planted, only 2 seeds grew.
Tresset [83]

Given:

For every 3 seeds Lara planted, only 2 seeds grew.

Altogether, 12 seeds grew.

To find:

The number of total seeds planted by Lara.

Solution:

It is given that for every 3 seeds Lara planted, only 2 seeds grew. It means the ratio of total seeds planted to seeds grew is 3:2.

Altogether, 12 seeds grew.

Let x be the number of total seeds planted by Lara. Then,

x:12=3:2

\dfrac{x}{12}=\dfrac{3}{2}

x=\dfrac{3}{2}\times 12

x=18

Therefore, the total number of seeds planter by Lara is 18.

3 0
3 years ago
A total of 234 tickets were sold for the school play. They were either adult tickets or student tickets. The number of student t
lorasvet [3.4K]
234 = a + s                                                       s = students       a = adults
2a = s
after you get the equations you solve. plug 2a into the above equation.
so u get 
234 = a + 2a 
234=3a then divide 3 from each side
78 = a
so 78 adult tickets were sold

3 0
3 years ago
Prove that 1/sin^2A -1/tan^2A= 1
Vika [28.1K]

Answer:

Step-by-step explanation:

LHS =\dfrac{1}{Sin^{2} \ A }-\dfrac{1}{Tan^{2} \ A }\\\\\\ = \dfrac{1}{sin^{2} \ A}- \dfrac{1}{\dfrac{Sin^{2} \ A}{Cos^{2} \ A}}\\\\\\= \dfrac{1}{sin^{2} \ A } - \dfrac{Cos^{2} \ A}{Sin^{2} \ A}\\\\\\= \dfrac{1-Cos^{2} \ A}{Sin^{2} \ A}\\\\\\= \dfrac{Sin^{2} \ A}{Sin^{2} \ A}\\\\\\= 1 = \ RHS

Hint: 1 - Cos² A = Sin² A

4 0
3 years ago
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