Question

jerrod has c baseball cards. Linda has 38 baseball cards, whih is 5 more than one-third the number jerrod has. whuch equation shows an equality between two different ways of expressing how many baseball cards linda has?

Answer 1

Answer:

We can express the number of baseball Linda has in two ways.

Either using variable c and y or using their values as follows,

$\Rightarrow y=5+\frac{1}{3}c$

or  $\Rightarrow 38=5+\frac{1}{3} \times 99$

Step-by-step explanation:

Given : Jerrod has c baseball cards and Linda has 38 baseball cards.

Also, number of baseball cards Linda has is 5 more than one-third the number Jerrod has.

Mathematically, it can be stated as ,

$\text{Number of baseball cards Linda has}=5+\frac{1}{3}c$

Let Linda has y number of baseball cards, then

$\Rightarrow y=5+\frac{1}{3}c$

Also, it is given Linda has 38 baseball cards, so y = 38

$\Rightarrow 38=5+\frac{1}{3}c$

From here we can solve for c,

$38-5=\frac{1}{3}c$

$33=\frac{1}{3}c$

$c=33 \times 3$

$\Rightarrow c=99$

Thus, Jerrod has 99 baseball cards.

We can express the number of baseball Linda has in two ways.

Either using variable c and y or using their values as follows,

$\Rightarrow y=5+\frac{1}{3}c$

or  $\Rightarrow 38=5+\frac{1}{3} \times 99$