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2 years ago

The dimensions of a rectangular building

Mathematics

2 answers:

Leona [35]2 years ago

7 0

15000 150*100 id say but don’t take ma word for it

galina1969 [7]2 years ago

6 0

Area of a rectangle is length x width.

So the area is 15000 because 150 x 100 = 15000

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(10 POINTS AND BRAINLIEST FOR BEST)

Naddik [55]

Answer:

C. II only

Step-by-step explanation:

Basically all you need do is plug these answers in and if the complete the inequality to make a true statement.

Yes i know no body want to do that but that whats need to be done lol.

once i plug 7 12/7+8 = 12.83

12.83>20

is incorrect

so we need continue

7*2.5+8>20

7*2.5= 17.5

17.5+8= 25.5

25.5>20

this a true statement

so we know 2.5 is an answer

now we need plug in -3

7*-3= -21

-21 +8 = -13

-13>20

this is incorrect

6 0

3 years ago

Look at photo because I don’t get it

steposvetlana [31]

Answer:

a) (-2,2), (-1,-1), (1,-1), (3,7)

b) x=1.4

8 0

3 years ago

Read 2 more answers

camille rides the bus to work. to get downtown,she can ride any bus number between 11 and 34, that can be divided evenly by 3, a

almond37 [142]

Answer:

12, 18, 24, 30

Step-by-step explanation:

List the numbers between 11 and 34 that can be evenly divided by 3:

12, 15, 18, 21, 24, 27, 30, 33

Then eliminate the odd numbers, obtaining:

12, 18, 24, 30

These are the four busses that Camille could ride to work.

7 0

3 years ago

. Exam scores for a large introductory statistics class follow an approximate normal distribution with an average score of 56 an

Andru [333]

Answer:

0.1% probability that the average score of a random sample of 20 students exceeds 59.5.

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a random variable X, with mean $\mu$ and standard deviation $\sigma$ , a large sample size can be approximated to a normal distribution with mean $\mu$ and standard deviation $\frac{\sigma}{\sqrt{n}}$

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 56, \sigma = 5, n = 20, s = \frac{5}{\sqrt{20}} = 1.12$

What is the probability that the average score of a random sample of 20 students exceeds 59.5?

This is 1 subtracted by the pvalue of Z when $X = 59.5$ . So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{59.5 - 56}{1.12}$

$Z = 3.1$

$Z = 3.1$ has a pvalue of 0.9990.

So there is a 1-0.9990 = 0.001 = 0.1% probability that the average score of a random sample of 20 students exceeds 59.5.

3 0

3 years ago

The length of a rectangle is 5 more than the width. The area is 126 square feet. Find the length and width of the rectangle.

solmaris [256]

The length of the rectangle is 14 feet and the width of the rectangle is 9 feet.

The length of a rectangle is 5 more than the width. The area is 126 square feet.

We need to find the length and width of the rectangle.

<h3>What is the area of a rectangle?</h3>

The area of a rectangle is calculated by multiplying the rectangle's length by its width.

Let the width of the rectangle be x, then the length of the rectangle be x+5.

We know that the area of the rectangle = Length×Width

Now, the area of the rectangle = (x+5)×x=126 square feet.

⇒ $x^{2}+5x-126=0$

⇒ $x^{2}+14x-9x-126=0$

⇒ $x(x+14)-9(x+14)=0$

⇒ $x=-14, x=9$ .

Since length cannot be a negative integer.

So, Width=9 feet and Length=9+5=14 feet.

Hence, the length of the rectangle is 14 feet and the width of the rectangle is 9 feet.

To know more about the area of the rectangle visit:

brainly.com/question/20693059

#SPJ1

3 0

1 year ago