Answer: (1, 4)
Explanation: When using the method of elimination, the goal is to eliminate a variable by either adding or subtracting the 2 equations. For this question, you can choose either to eliminate X or Y. I’ll eliminate X as an example:
In order to eliminate a variable, the same variable in both equations must have the same coefficient.
(1) 3x+y=7
(2) 2x+5y=22
Multiply (1) by 2:
(3) 6x+2y=14
Multiply (2) by 3:
(4) 6x+15y=66
Now that X in both equations has the same coefficient of 6, you can subtract the two equations to officially eliminate the variable and solve for Y:
Subtract (4) from (3):
-13y=-52
y=4
Now that you have the value of Y, substitute that into either one of the equations to get X. I’ll use the first equation as an example:
3x+(4)=7
3x=3
x=1
Therefore, the point of intersection is (1, 4).
Hope this helps シ
Answer:
<h2>BR ≈ 49.0</h2>
Step-by-step explanation:
Use cosine:
We have
Substitute:
<em>cross multiply</em>
<em>divide both sides by 8,572</em>
Answer:
8.80
hope this helps :)
Step-by-step explanation:
since it is 3% you have to divide it by 3,408
[3%]/[3,408]= 8.80
Part A: each tricycle has three wheels, so with 48 wheels the number of tricycles was a =48/3=16 tricycles.
t=w/3 (the number of tricycles is the number of wheels divided by 3)
Part B:
The number of seats:
24=b+a (so b=24-a)
The number of seats is the sum of one seat per bicycle and one seat per a tricycle
also, 61=2a+3b (the number of wheels)
So we have:
24=b+a
b=24-a
We can substitute this for b:
61=2a+3(24-a)
and solve:
61=2a+3*24-3a
61=72-a
a=72-61
a=11
There were 11 bicycles!!
and there were 24-11 tricycles, so 13 tricycles.
Part C: each of the bikes has only one front-steering handlebar, so there were a total of 144 vehicles:
a+b+c=144
There were 378 pedals. And the number of pedals is:
2a+2b+4c=378 (the numbers 2,2,4 represent the number of pedals per vehicle)
divide by 2:
a+b+2c=189
Now, we have
a+b+2c=189
and
a+b+c=144
and we can subtract them from each other:
a+b+c-(a+b+2c)=144-189
-c=45
c=45, so there were 45 tandem bicycles!
(this also means that a+b=144-45, that is a+b=99)
now the wheels:
3a+2b+2c=320
Let's substitute c:
3a+2b+90=320
which is
3a+2b=240
We also know that a+b=99, so we can substract this from this equation:
3a+2b+-a-b=240-99
2a+b=141
and again:
2a+b-a-b=141-99
a=42 - there were 42 trycicles!!!
And the bicycles were the rest:
99-42=57 bycicles
