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3 years ago

Carl walked 12m north then turned around and walked back 4m south. What was his

Chemistry

1 answer:

aleksklad [387]3 years ago

3 0

Answer:

Distance: 16m Displacement: 8m North

Explanation:

Total distance is the total amount traveled, regardless of direction. So, you would just add 12 and 4 to get a total distance of 16m. Displacement is the distance/direction from the start to the end point, regardless of which way you got there. So, to find displacement, you just subtract:

12m North - 4m South = 8m North

** I could be wrong so definitely double check this answer with a similar question**

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Balance the equation:2Na+3H2O-2NaOH+H2

aleksandrvk [35]

Answer:

2Na + 2H2O → 2NaOH + H2

Explanation:

A balanced equation is an equation for a chemical reaction in which the number of atoms for each element in the reaction and the total charge are the same for both the reactants and the products.

7 0

3 years ago

What isotope has 13 protons and 14 neutrons? Enter the name of the element followed by a hyphen and the mass number (e.g., urani

Lilit [14]

Answer: The element is represented as Aluminium-27

Explanation:

Atomic number is defined as the number of protons or number of electrons that are present in an electrically neutral atom.

Atomic number = Number of electrons = Number of protons = 13

Mass number is defined as the sum of number of protons and neutrons that are present in an atom.

Mass number = Number of protons + Number of neutrons = 13 + 14 = 27

Thus the element with atomic number of 13 is aluminium and its mass number is 27. Thus it is represented as Aluminium-27

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4 years ago

2K + 2HBr → 2 KBr + H2

Inessa [10]

Answer:

$\large \boxed{\text{0.0503 g}}$

Explanation:

The limiting reactant is the reactant that gives the smaller amount of product.

Assemble all the data in one place, with molar masses above the formulas and masses below them.

M_r: 39.10 80.41 2.016

2K + 2HBr ⟶ 2KBr + H₂

m/g: 5.5 4.04

a) Limiting reactant

(i) Calculate the moles of each reactant

$\text{Moles of K} = \text{5.5 g} \times \dfrac{\text{1 mol}}{\text{31.10 g}} = \text{0.141 mol K}\\\\\text{Moles of HBr} = \text{4.04 g} \times \dfrac{\text{1 mol}}{\text{80.91 g}} = \text{0.049 93 mol HBr}$

(ii) Calculate the moles of H₂ we can obtain from each reactant.

From K:

The molar ratio of H₂:K is 1:2.

$\text{Moles of H}_{2} = \text{0.141 mol K} \times \dfrac{\text{1 mol H}_{2}}{\text{1 mol K}} = \text{0.0703 mol H}_{2}$

From HBr:

The molar ratio of H₂:HBr is 3:2.

$\text{Moles of H}_{2} = \text{0.049.93 mol HBr } \times \dfrac{\text{1 mol H}_{2}}{\text{1 mol HBr}} = \text{0.024 97 mol H}_{2}$

(iii) Identify the limiting reactant

HBr is the limiting reactant because it gives the smaller amount of NH₃.

b) Excess reactant

The excess reactant is K.

c) Mass of H₂

$\text{Mass of H}_{2} = \text{0.024 97 mol H}_{2} \times \dfrac{\text{2.016 g H}_{2}}{\text{1 mol H}_{2}} = \textbf{0.0503 g H}_{2}\\ \text{The mass of hydrogen is $\large \boxed{\textbf{0.0503 g}}$ }$

3 0

3 years ago

draw the structures for and name and classify as primary, secondary, or tertiary all the isomeric amines with the molecular form

enyata [817]

The amine compounds are those compounds that contain nitrogen attached to the carbon chain.

<h3>What is an amine?</h3>

Thee term amine refers to a compound that contains the amine group (-NH2). The amine compounds are those compounds that contain nitrogen attached to the carbon chain.

I have shown three structures that correspond to the formula C5H13N. The names of the structures are also shown. From left to right, all the structures that are shown are all tertiary amines.

Learn more about amines;brainly.com/question/28167507

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