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finlep [7]
3 years ago
8

Methyl orange can change color by transitioning from one chromophore to another. When added to a clear solution and the solution

turns red, it is determined to be a(n) __________ in its __________ stable form.
Chemistry
1 answer:
Anvisha [2.4K]3 years ago
4 0

Answer:

acidic titration in its stable form

Explanation:

Methyl orange can change its color in titration solution. The yellow color is towards alkaline solution and red color is towards acidic solution. The Ph value of solution will change during this chemical process.

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Explain, in terms of particles, what happens when methane boils and why
Ronch [10]

Answer:Butane > ethane > methane, because between bigger molecules there are stronger van der Waals forces and also higher molar mass means they need to be given more energy to have enough kinetic energy to move quickly, freely in gas.

There are multiple butene isomers (Butene) and some (2-Butenes - cis and trans) actually have higher boiling point than n-Butane (there is also Isobutane, of course, with quite much lower boiling point than all of them) and some (1-Butene, Isobutylene) have lower, so this isn't really a fair or simple question. But on simplest level, it can again be said that 1-butene has lower boiling point because it has very similar shape but slightly lower molar mass (2H less) than n-butane.

Explanation:

3 0
2 years ago
What is Dalton's law of partial pressure
Leto [7]
  • If 3 substances be x,y,z

\\ \tt\longmapsto P_{net}=P_x+P_y+P_z

Where

\\ \tt\longmapsto P_x=\dfrac{n_xRT}{V}

\\ \tt\longmapsto P_y=\dfrac{n_yRT}{V}

\\ \tt\longmapsto P_z=\dfrac{n_zRT}{V}

  • P is partial pressure
  • n is number of moles
  • V is volume
  • T is temperature
7 0
3 years ago
Read 2 more answers
g We've all blown up balloons. When you blow into a balloon, you are putting in more moles of gas. Let's say that on the second
guapka [62]
G We've all blown up balloons. When you blow into a balloon, you are putting in more moles of gas. Let's say that on the second exhalation (blow) you blow in the exact same number of moles as you did with the first exhalation. So, you doubled the number of moles in the balloon. If the temperature and pressure remained constant, what is true about the volume of the gas in the balloon
8 0
3 years ago
The illustration above represents what concept?
Nitella [24]

Answer:

3 Is D

Explanation:

6 0
3 years ago
A solid mixture consists of 47.6g of KNO3 (potassium nitrate) and 8.4g of K2SO4 (potassium sulfate). The mixture is added to 130
IgorLugansk [536]

<u>Answer:</u> No crystals of potassium sulfate will be seen at 0°C for the given amount.

<u>Explanation:</u>

We are given:

Mass of potassium nitrate = 47.6 g

Mass of potassium sulfate = 8.4 g

Mass of water = 130. g

Solubility of potassium sulfate in water at 0°C = 7.4 g/100 g

This means that 7.4 grams of potassium sulfate is soluble in 100 grams of water

Applying unitary method:

In 100 grams of water, the amount of potassium sulfate dissolved is 7.4 grams

So, in 130 grams of water, the amount of potassium sulfate dissolved will be \frac{7.4}{100}\times 130=9.62g

As, the soluble amount is greater than the given amount of potassium sulfate

This means that, all of potassium sulfate will be dissolved.

Hence, no crystals of potassium sulfate will be seen at 0°C for the given amount.

7 0
3 years ago
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