4 years ago

How many grams of sodium chloride are present in a 0.75 M solution with a volume of 500.0 mililiters

1 answer:

5 0

C = 0,75 mol/dm³
V = 500mL = 500cm³ = 0,5dm³

C = n/V
n = 0,75×0,5dm³
n = 0,375 moles

M NaCl: 23+35,5 = 58,5g

1 mole ---------- 58,5g
0,375 ----------- X
X = 0,375×58,5
X = 21,9375g NaCl

:)

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