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prohojiy [21]
2 years ago
8

Calculate the pH of a solution that is 0.113 M HCI.

Chemistry
1 answer:
Alex Ar [27]2 years ago
6 0

Simplified concentration

\\ \rm\Rrightarrow 1.13\times 10^{-2}M

Now

\\ \rm\Rrightarrow pH=-log[H^+]

\\ \rm\Rrightarrow pH=-log(1.13\times 10^{-2})

\\ \rm\Rrightarrow pH=-log1.13-log10^{-2}

\\ \rm\Rrightarrow pH=-0.05+2

\\ \rm\Rrightarrow pH=1.95

Highly acidic

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The rate constant : k = 9.2 x 10⁻³ s⁻¹

The half life : t1/2 = 75.3 s

<h3>Further explanation</h3>

Given

Reaction 45% complete in 65 s

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A = 0.55

Ao = 1

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ln A = -kt + ln Ao

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-0.598=-k.65

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