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1 year ago

Calculate the pH of a solution that is 0.113 M HCI.

Chemistry

1 answer:

Alex Ar [27]1 year ago

6 0

Simplified concentration

$\\ \rm\Rrightarrow 1.13\times 10^{-2}M$

Now

$\\ \rm\Rrightarrow pH=-log[H^+]$

$\\ \rm\Rrightarrow pH=-log(1.13\times 10^{-2})$

$\\ \rm\Rrightarrow pH=-log1.13-log10^{-2}$

$\\ \rm\Rrightarrow pH=-0.05+2$

$\\ \rm\Rrightarrow pH=1.95$

Highly acidic

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Sophie [7]

Answer:

a) the atomic number is 15

b) the mass number is 15+16 = 31

c) element is phosphorus

d)Group 15 period 3

6 0

2 years ago

Ammonia gas will react with oxygen gas to yield nitrogen monoxide gas and water vapor.

ruslelena [56]

Answer:

a) 0.168 moles O2

b) 9.50 grams O2

c) 0.01662 kg NO

d)88.9 %

Explanation:

Step 1: Data given

Molar mass of NH3 = 17.03 g/mol

Molar mass of O2 = 32 g/mol

Molar mass of NO = 30.01 g/mol

Molar mass of H2O = 18.02 g/mol

Step 2: The balanced equation:

4NH3 + 5O2 → 4NO + 6H2O

a. How many moles of ammonia will react with 6.73g of oxygen?

Calculate moles of oxygen = mass O2/ molar mass O2

moles oxygen = 6.73 grams / 32.00 g/mol = 0.210 moles

Calculate moles of NH3

For 4 moles of NH3 we need 5 moles O2 to produce 4 moles NO and 6 moles H2O

For 0.210 moles O2 we need 4/5 *0.210 = 0.168 moles O2

b. If 6.42g of water is produced, how many grams of oxygen gas reacted?

Calculate moles of H2O = 6.42 grams / 18.02 g/mol = 0.356 moles

Calculate moles of O2:

For 4 moles of NH3 we need 5 moles O2 to produce 4 moles NO and 6 moles H2O

For 0.356 moles H2O we'll need 5/6 * 0.356 = 0.297 moles O2

Calculate mass of O2 = moles O2 * molar mass O2

Mass O2 = 0.297 moles O2 * 32.00 g/mol = 9.50 grams O2

c. If the reaction uses up 9.43105 g of ammonia, how many kilograms of nitrogen monoxide will be formed?

Calculate moles of ammonia = 9.43105 grams / 17.03 g/mol =0.5538 moles

Calculate moles of NO:

For 4 moles of NH3 we need 5 moles O2 to produce 4 moles NO and 6 moles H2O

For 0.5538 moles of NH3 we'll have 0.5538 moles NO

Calculate mass of NO

Mass NO = 0.5538 moles * 30.01 g/mol = 16.62 grams = 0.01662 kg NO

d. When 2.51 g of ammonia react with 3.76 g of oxygen, 2.27 g of water vapor are produced. What is the percentage yield of water?

Calculate moles of NH3 = 2.51 grams / 17.03 g/mol = 0.147 moles

Calculate moles of O2 = 3.76 grams / 32 g/mol = 0.118 moles

Determine the limiting reactant

O2 is the limiting reactant, it will completely be consumed (0.118 moles)

NH3 is in excess. There will react 4/5 * 0.118 = 0.0944 moles

There will remain 0.147 - 0.0944 = 0.0526 moles

Calculate moles H2O: For 0.118 moles O2 we'll have 6/5 * 0.118 = 0.1416 moles H2O

Calculate mass H2O = 0.1416 moles * 18.02 g/mol = 2.552 grams H2O

Calculate % yield = (2.27/2.552)*100 % = 88.9 %

4 0

2 years ago

A sample of helium gas inside a closed but flexible container occupies a volume of 355mL at 23°C. If the pressure is held consta

guapka [62]

Answer:

978.19° C

Explanation:

P1V1/T1 =P2V2/T2 Since the pressure is constant, this can be written as

V1/T1 = V2/T2 RE-ARRANGE TO

V2 * T1/V1 = T2 Note: T must be in Kelvin!!

1.5 L * (273.15 + 23) / (.355 L ) = T2 = 1251.338 K =978.19 C

6 0

1 year ago

Balance the following equations:

GuDViN [60]

ANSWERS :-

1)

$\red{2}Na + Br2 → \red{2}NaBr$

2)

$\blue{2}C4H6 + \blue{11}O2 → \blue{8}CO2 + \blue{6}H2O$

3)

$H3PO4 + \green{3}LiOH → \green{3}H2O + Li3PO4$

4)

$Ca(NO3)2 + K2SO4 → CaSO4 + \pink{2}KNO3$

5)

$\orange{2}H2O2→\orange{2}H2O+O2$

(mark me brainliest please I need 3 more :))

$\large\sf\red{thank \: you}$

8 0

2 years ago

What type of chemical reactions are molecules joined together to form more complex molecules?

Komok [63]

Answer:

Anabolic reaction are specific type of reaction in which molecules joined together to form more complex molecules.

Explanation:

Metabolic reactions are catagorized into 2 types

1 Catabolic reactions: chemical or biochemical reactions that helps in the breakdown of complex molecules such as lipid,proteins and carbohydrates to convert them into their monomeric substituents such as fatty acid,amino acids and monosaccharides. Catabolism or breakdown of macromolecules proceed with the generation of free energy in form of ATP.

2 Anabolic reactions : Anabolic reactions can be defined as chemical or biochemical reactions in which molecules are joined to form more complex molecules.For examples monosaccharides can be joined by glycosidic linkages to form polysaccharides,amino acids can be joined with peptide bonds to form polypeptide chains which further constitute a protein.Anabolic reactions requires free energy from outside source .

3 0

3 years ago