Question

Calculate the pH of a solution that is 0.113 M HCI.

Answer 1

Simplified concentration

$\\ \rm\Rrightarrow 1.13\times 10^{-2}M$

Now

$\\ \rm\Rrightarrow pH=-log[H^+]$

$\\ \rm\Rrightarrow pH=-log(1.13\times 10^{-2})$

$\\ \rm\Rrightarrow pH=-log1.13-log10^{-2}$

$\\ \rm\Rrightarrow pH=-0.05+2$

$\\ \rm\Rrightarrow pH=1.95$

Highly acidic