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1 year ago

Calculate the pH of a solution that is 0.113 M HCI.

Chemistry

1 answer:

Alex Ar [27]1 year ago

6 0

Simplified concentration

$\\ \rm\Rrightarrow 1.13\times 10^{-2}M$

Now

$\\ \rm\Rrightarrow pH=-log[H^+]$

$\\ \rm\Rrightarrow pH=-log(1.13\times 10^{-2})$

$\\ \rm\Rrightarrow pH=-log1.13-log10^{-2}$

$\\ \rm\Rrightarrow pH=-0.05+2$

$\\ \rm\Rrightarrow pH=1.95$

Highly acidic

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Oduvanchick [21]

Time taken for star to reach Earth = 7.5 years

<h3>Further explanation</h3>

Given

7.5 light years(distance Earth-star)

Required

Time taken

Solution

Speed of light=v = 3 x 10⁸ m/s

1 light years = 9.461 × 10¹⁵ m= distance(d)

So time taken for 1 light years :

time(t) = distance(d) : speed(v)

t = 9.461 × 10¹⁵ m : 3 x 10⁸ m/s

t = 3.154 x 10⁷ s = 1 years

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2 years ago

Arrange the three common unit cells in order from least dense to most dense packing. a. face-centered cubic < body-centered c

maks197457 [2]

Answer:

b. primitive cubic < body-centered cubic < face-centered cubic

Explanation:

The coordination number is defined as the number of atoms (or ions) surrounding an atom (or ion) in a crystal lattice. Its value gives us a measure of how tightly the spheres are packed together. The larger the coordination number, the closer the spheres are to each other.

In the primitive cubic, each sphere is in contact with 6 spheres, so its coordination number is 6.

In the body-centered cubic, each sphere is in contact with 8 spheres, so its coordination number is 12.

In the face-centered cubic, each sphere is in contact with 12 spheres, so its coordination number is 12.

Therefore, the increasing order in density is the primitive cubic first, then the body-centered cubic, and finally the face-centered cubic.

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2 years ago

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postnew [5]

Thomson's atomic model is a theory about the atomic structure proposed in 1904 by Thomson, who discovered the electron in 1897, a few years before the discovery of the proton and the neutron.

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2 years ago

Read 2 more answers

When methyloxirane is treated with HBr, the bromide ion attacks the less substituted position. However, when phenyloxirane is tr

konstantin123 [22]

Answer:

See explanation and picture below

Explanation:

First, in the case of methyloxirane (Also known as propilene oxide) the mechanism that is taking place there is something similar to a Sn2 mechanism. Although a Sn2 mechanism is a bimolecular substitution taking place in only step, the mechanism followed here is pretty similar after the first step.

In both cases, the H atom of the HBr goes to the oxygen in the molecule. You'll have a OH⁺ in both. However, in the case of methyloxirane the next step is a Sn2 mechanism step, the bromide ion will go to the less substitued carbon, because the methyl group is exerting a steric hindrance. Not a big one but it has a little effect there, that's why the bromide will rather go to the carbon with more hydrogens. and the final product is formed.

In the case of phenyloxirane, once the OH⁺ is formed, the next step is a Sn1 mechanism. In this case, the bond C - OH⁺ is opened on the side of the phenyl to stabilize the OH. This is because that carbon is more stable than the carbon with no phenyl. (A 3° carbon is more stable than a 2° carbon). Therefore, when this bond opens, the bromide will go there in the next step, and the final product is formed. See picture below for mechanism and products.

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Answer:

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