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1 year ago

Calculate the pH of a solution that is 0.113 M HCI.

Chemistry

1 answer:

Alex Ar [27]1 year ago

6 0

Simplified concentration

$\\ \rm\Rrightarrow 1.13\times 10^{-2}M$

Now

$\\ \rm\Rrightarrow pH=-log[H^+]$

$\\ \rm\Rrightarrow pH=-log(1.13\times 10^{-2})$

$\\ \rm\Rrightarrow pH=-log1.13-log10^{-2}$

$\\ \rm\Rrightarrow pH=-0.05+2$

$\\ \rm\Rrightarrow pH=1.95$

Highly acidic

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