The average kinetic energy of 1 mole of a gas at -32 degrees Celsius is:
3.80 x 103 J
The relationship between volume and temperature of a gas, when pressure and moles of a gas are held constant, is: V*T = k.
FALSE
The relationship between moles and volume, when pressure and temperature of a gas are held constant, is: V/n = k. We could say then, that:
If the moles of gas are tripled, the volume must also triple.
If the temperature and volume of a gas are held constant, an increase in pressure would most likely be caused by an increase in the number of moles of gas.
TRUE
If the vapor pressure of a liquid is less than the atmospheric pressure, the liquid will not boil.
TRUE
35 - AB
36 - BD
33 - true
34 - False
20 - 6
21 - orthohombic
B that’s is not a chemical change because I took the test
Answer:
The Flow of science keeps going because not everything is fully discovered yet. New things are discovered everyday and are also made better as well.
Explanation:
Answer : The rate for a reaction will be 
Explanation :
The balanced equations will be:

In this reaction,
and
are the reactants.
The rate law expression for the reaction is:
![\text{Rate}=k[A]^2[B]^1](https://tex.z-dn.net/?f=%5Ctext%7BRate%7D%3Dk%5BA%5D%5E2%5BB%5D%5E1)
or,
![\text{Rate}=k[A]^2[B]](https://tex.z-dn.net/?f=%5Ctext%7BRate%7D%3Dk%5BA%5D%5E2%5BB%5D)
Now, calculating the value of 'k' by using any expression.
![\text{Rate}=k[A]^2[B]](https://tex.z-dn.net/?f=%5Ctext%7BRate%7D%3Dk%5BA%5D%5E2%5BB%5D)


Now we have to calculate the initial rate for a reaction that starts with 1.48 M of reagent A and 1.32 M of reagents B.
![\text{Rate}=k[A]^2[B]^0[C]^1](https://tex.z-dn.net/?f=%5Ctext%7BRate%7D%3Dk%5BA%5D%5E2%5BB%5D%5E0%5BC%5D%5E1)


Therefore, the rate for a reaction will be 