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Ira Lisetskai [31]
3 years ago
7

Which type of chemical reaction does this word equation exemplify: iron metal plus copper (II) sulfate solution yields iron (II)

sulfate solution and copper metal?
Chemistry
2 answers:
olchik [2.2K]3 years ago
4 0

Answer: Single replacement

Fe+CuSO_4\rightarrow Cu+FeSO_4

Explanation:

Single replacement reaction is a chemical reaction in which more reactive element displaces the less reactive element from its salt solution.

Iron being more reactive than copper would displace copper from its salt solution and thus will generate copper and iron sulphate.

The chemical equation representing iron metal plus copper (II) sulfate solution yields iron (II) sulfate solution and copper metal is:

Fe+CuSO_4\rightarrow Cu+FeSO_4

yan [13]3 years ago
3 0

Answer:

Synthesis

Explanation:

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Answer:

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8 0
3 years ago
State Hund's rule.
loris [4]

Answer:

C. The lowest-energy electron configuration of an atom has the maximum number of unpaired electrons, all of which have the same spin, in degenerate orbitals.

Explanation:

The Hund's rule is used to place the electrons in the orbitals is it states that:

1. Every orbital in a sublevel is singly occupied before any orbital is doubly occupied;

2. All of the electrons in singly occupied orbitals have the same spin.

So, the electrons first seek to fill the orbitals with the same energy (degenerate orbitals) before paring with electrons in a half-filled orbital. Orbitals doubly occupied have greater energy, so the lowest-energy electron configuration of an atom has the maximum number of unpaired electrons, and for the second statement, they have the same spin.

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6 0
3 years ago
Two hydrogen atoms collide in a head on collision and end up with zero kinetic energy. Each then emits a photon of 121.6 nm (n=2
Zinaida [17]

Explanation:

Expression for the kinetic energy is as follows.

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Now, total kinetic energy will be as follows.

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Since, this energy converts into electromagnetic radiation of wavelength 121.6 nm.

Relation between energy and photon is as follows.

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                                = \frac{6.626 \times 10^{-34} \times 3 \times 10^{8}}{121.6 \times 10^{-9}}

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          v = \sqrt{\frac{1.63 \times 10^{-18}}{1.67 \times 10^{-27}}

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Thus, we can conclude that atoms were moving at a speed of 3.12 \times 10^{4} m/s before the collision.

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4 years ago
Drag the tiles to the correct boxes to complete the pairs.
7nadin3 [17]

The correct answer is B.

Have a great day!

3 0
3 years ago
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