Answer:
x=3,5
Explanation:
x2−8x+15=0
Try to express the terms of the equation in square form.
Adding 16 both sides of the equation,
(x2−2⋅x⋅4+42)+15=16
or,(x−4)2+15−16=0
or,(x−4)2−1=0
or,(x−4)2−12=0
This is the a2−b2=(a+b)(a−b)form.
(x−4+1)(x−4−1)=0
or,(x−3)(x−5)=0
Now, equate both the terms to zero since both of them when multiplied, give zero.
Either,
x−3=0
∴x=3
Or,
x−5=0
∴x=5
Ans:x=3,5 Hope this helpsXD...!!
<h3>Answer:</h3>
Equation of the ellipse = 3x² + 5y² = 32
<h3>Step-by-step explanation:</h3>
<h2>Given:</h2>
- The centre of the ellipse is at the origin and the X axis is the major axis
- It passes through the points (-3, 1) and (2, -2)
<h2>To Find:</h2>
- The equation of the ellipse
<h2>Solution:</h2>
The equation of an ellipse is given by,

Given that the ellipse passes through the point (-3, 1)
Hence,

Cross multiplying we get,
- 9b² + a² = 1 ²× a²b²
- a²b² = 9b² + a²
Multiply by 4 on both sides,
- 4a²b² = 36b² + 4a²------(1)
Also by given the ellipse passes through the point (2, -2)
Substituting this,

Cross multiply,
- 4b² + 4a² = 1 × a²b²
- a²b² = 4b² + 4a²-------(2)
Subtracting equations 2 and 1,
- 3a²b² = 32b²
- 3a² = 32
- a² = 32/3----(3)
Substituting in 2,
- 32/3 × b² = 4b² + 4 × 32/3
- 32/3 b² = 4b² + 128/3
- 32/3 b² = (12b² + 128)/3
- 32b² = 12b² + 128
- 20b² = 128
- b² = 128/20 = 32/5
Substituting the values in the equation for ellipse,


Multiplying whole equation by 32 we get,
3x² + 5y² = 32
<h3>Hence equation of the ellipse is 3x² + 5y² = 32</h3>
The area is equal to 230 CM.
area for rectangle :
area = width times length
area = 7 x 20 = 140CM
area for triangle:
area = 1/2 times base times height
area = 1/2 x 20 x 9 = 90CM
ADD:
140+90 = 230 CM
Answer: y = -1/2
Step-by-step explanation:
Subtract both sides by 7/8
y = 3/8 - 7/8
Then combine like terms
y = -4/8
Then simplify
y = -1/2
Answer:
2cnd one 3rd one 4th one last one
Step-by-step explanation: