Answer:
11.1714
Step-by-step explanation:
Just use a calculator! :)
Answer:
Proved,
P(A∪B)=0.72
Step-by-step explanation:
Sue travels by bus or walks when she visits the shops.
Probability( catch the bus to the shop ), P(A) = 0.4
Probability( catch the bus from the shop ), P(B) = 0.7
Both A and B are independent events.
Therefore,
P(A∩B) = 0.4×0.7
= 0.28
Probability Sue walks one way = 1 - P(A∩B)
= 1 - 0.28
= 0.72
Hence, the probability that Sue walks at one way is 0.72
<span>2² + 4² ÷ 2<span>²
4 + 16 </span></span>÷ 4
4 + 4
8
Answer:x=-4 and x=4
Step-by-step explanation:
Took the assignment on edg 2020