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alex41 [277]
3 years ago
10

Two aqueous NaCl solutions of equal volume and concentration were kept in flasks and held at different temperatures. The two sol

utions were combined in a larger flask. Based on this information, What will be the prediction?
Chemistry
1 answer:
Alexxx [7]3 years ago
5 0

Answer:

Effervescence of the one with high temperature will.occur

Explanation:

You might be interested in
Which are the product(s) of this chemical reaction? FeCl 3 + 3NH 4OH ->
Vinvika [58]
The answer is D

FeCl3 + 3 NH4OH → Fe(OH)3 + 3 NH4Cl
5 0
2 years ago
How can you tell from the name the types of bonds present in a hydrocarbon?
Darya [45]

Answer:

Alkane

Alkene

Alkyne

Explanation:

Alkane=1 bond (Saturated hydrocarbon)

Alkene= 2 bonds (Unsaturated hydrocarbon)

Alkyne= triple bonds (Unsaturated hydrocarbon)

Formula of Alkane = CnH2n+2

Formula of Alkene = CnH2n

Formula of Alkyne = CnH2n-2

7 0
3 years ago
Balance the following skeleton reactions and identify the oxidizing and reducing agents:(b) P₄(s) → HPO₃²⁻(aq) + PH₃(g) [acidic]
m_a_m_a [10]

The balanced chemical equation is :

5P₄ + 36OH → 12HPO₃⁻² (aq) + 8PH₃ (acidic)

Here the oxidation number of P changed from 0 to -3 in PH₃ and increases  from 0 to +3 in HPO₃⁻². When P₄ changes to PH₃ reduction reaction is taking place as there is addition of hydrogen and when P₄ changes to HPO₃⁻² oxidation takes place as there is addition of oxygen.

Thus clearly both reduction and oxidation are taking place.

Thus, we can infer that here P₄ is both oxidizing as well as reducing agent.

To know more about oxidation number here:

brainly.com/question/13182308

#SPJ4

5 0
2 years ago
2. How many moles are in 8.30 x 1023 molecules of H2O?
daser333 [38]

Answer:

<h2>1.38 moles</h2>

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

n =  \frac{N}{L} \\

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

n =  \frac{8.30 \times  {10}^{23} }{6.02 \times  {10}^{23} }  =  \frac{8.30}{6.02}  \\  = 1.3787 37...

We have the final answer as

<h3>1.38 moles</h3>

Hope this helps you

8 0
3 years ago
If i add 25 mL of water to 125 mL of a 0.15 M NaOH solution, what will the molarity of the diluted solution be ?
marshall27 [118]
1000 mL=1L

25 mL = 0.025 L
125 mL = 0.125 L

M1V1=M2V2
0.15(0.125) = M2(0.025)
0.01875 = M2(0.025)
0.75 = M2

0.75 M
6 0
3 years ago
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