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alex41 [277]
3 years ago
10

Two aqueous NaCl solutions of equal volume and concentration were kept in flasks and held at different temperatures. The two sol

utions were combined in a larger flask. Based on this information, What will be the prediction?
Chemistry
1 answer:
Alexxx [7]3 years ago
5 0

Answer:

Effervescence of the one with high temperature will.occur

Explanation:

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In an effort to try winning World War I, many countries broke previously created treaties and pacts that banned the use of chemi
nadya68 [22]

D the belguim people atacked using it

3 0
3 years ago
Phosgene is a highly toxic gas made up of carbon, oxygen, and chlorine atoms. Its density at 1.05 atm and 258C is 4.24 g/L. (a)
VikaD [51]

Answer:

Molar mass = 99 g/mol

Explanation:

Phosgene contains carbon, oxygen and chlorine atoms. Its molecular formular is; COCl2

The molar mass is given as the sum off the individual atomic mass of the elements in the compound.

Molar mass = C + O + 2Cl

Molar mass = 12 + 16 + 2(35.5)

Molar mass = 99 g/mol

5 0
3 years ago
How many minutes will it take to plate out 4.50 g of Cu from a solution of Cu(NO3)2 (aq) onto the cathode of an electrolytic cel
ipn [44]

Answer:

It will take 28.5 minutes

Explanation:

<u>Step 1: </u>Data given

Mass of Cu = 4.50 grams

8.00 A of current are used

Molar mass of Cu = 63.5 g/mol

Step 2: Calculate time needed

Cu2+ →Electricity → Cu

we notice a flow of 2 electrons ⇒ This means the Faraday constant = 2F

Since Molar mass of Cu is 63.5 g/mol

63.5 grams of Cu is deposited by 2*96500 C

4.50 grams of Cu ((2*96500)/63.5)  * 4.50 = 13677.17 C

Q = It

13677.17 = 8t*60 seconds

t = 28.5 minutes

3 0
3 years ago
What are the formulas for the ionic compounds named sodium iodide and magnesium iodide
bixtya [17]

Sodium Iodide: NaI

Magnesium Iodide: MgI2

8 0
3 years ago
An element consists of two isotopes. One with a mass of 79.95 amu and an abundance of 29.9%. The second isotope has a mass of 81
galina1969 [7]

 the molar  mass of the element  is  81.36 g/mol

<u><em>calculation</em></u>

step 1 : multiply  each %abundance  of the isotope  by   its mass  number

that is 79.95 x 29.9 =2391

           81.95 x 70.1  = 5745

Step 2: add them together

2390.5 + 5744.7 =8136

Step 3: divide by 100

= 8136/100 = 81.36  g/mol

5 0
3 years ago
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