Answer:
Mars
Explanation:
Terrestrial or inner planets like Mars and Venus were formed near the Sun where the solar system's temperatures were very high.
Answer:
1 gramo de metano aporta 50.125 kilojoules.
1 gramo de metano aporta 48.246 kilojoules.
Explanation:
La cantidad de energía liberada por la combustión de una unidad de masa del hidrocarburo (
), en kilojoules por mol, es igual a la cantidad de energía liberada por mol de compuesto (
), en kilojoules por mol, dividido por su masa molar (
), en gramos por mol:
(1)
A continuación, analizamos cada caso:
Metano
![Q = \frac{802\,\frac{kJ}{mol} }{16\,\frac{g}{mol} }](https://tex.z-dn.net/?f=Q%20%3D%20%5Cfrac%7B802%5C%2C%5Cfrac%7BkJ%7D%7Bmol%7D%20%7D%7B16%5C%2C%5Cfrac%7Bg%7D%7Bmol%7D%20%7D)
![Q = 50.125\,\frac{kJ}{g}](https://tex.z-dn.net/?f=Q%20%3D%2050.125%5C%2C%5Cfrac%7BkJ%7D%7Bg%7D)
1 gramo de metano aporta 50.125 kilojoules.
Octano
![Q = \frac{5500\,\frac{kJ}{mol} }{114\,\frac{g}{mol} }](https://tex.z-dn.net/?f=Q%20%3D%20%5Cfrac%7B5500%5C%2C%5Cfrac%7BkJ%7D%7Bmol%7D%20%7D%7B114%5C%2C%5Cfrac%7Bg%7D%7Bmol%7D%20%7D)
![Q = 48.246\,\frac{kJ}{mol}](https://tex.z-dn.net/?f=Q%20%3D%2048.246%5C%2C%5Cfrac%7BkJ%7D%7Bmol%7D)
1 gramo de metano aporta 48.246 kilojoules.
With all of the information given (pressure, volume, temperature, and the molar mass), we need a formula that relates this all together. The formula we need is the ideal gas law, PV=nRT. Since the pressure is defined in millimeters of mercury, we need the R value that correlates with this, which is 62.4; on top of this, we need the temperature in Kelvin - simply add 273.15 to convert from Celsius. With all of this information, simply plug-and-chug:
PV=nRT
(800)(3.7) = n(62.4)(37 + 273.15)
n = 0.1529 moles
Finally, the problem is asking the amount of air in grams. We have moles, so all we need to do is multiply that value by the molar mass.
0.1529 moles x 29 grams per mole =
4.435 grams of air
The balloon has 4.435 grams of air inside it.
Hope this helps!
It is 0.5474 but you can put 0.5 hope this helps