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3 years ago

How many moles of nitrogen are in 2.0×10−2mole of quinine?

Chemistry

1 answer:

galben [10]3 years ago

7 0

Answer: 4 x 10 ∧-2 moles of nitrogen.

Explanation:

The chemical formular for quinine is ; C20 H24 N2 O2

As can be seen from the chemical formular;

1 mole of quinine contains 2 moles of Nitrogen

Thus; 2.0 x 10 ∧-2 moles of quinine would contain

2.0 x 10 ∧-2 x 2 = 4 x 10 ∧-2 moles of nitrogen.

Therefore 4 x 10 ∧-2 moles of nitrogen are in 2.0×10−2mole of quinine

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$d=0.92\frac{kg}{m^{3}}$

Explanation:

Using the Ideal Gas Law we have $PV=nRT$ and the number of moles n could be expressed as $n=\frac{m}{M}$ , where m is the mass and M is the molar mass.

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Answer:

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Explanation:

From the balanced reaction:

Mg + 1/2O₂ → MgO,

1.0 mole of Mg reacts with 0.5 mole of oxygen to produce 1.0 mole of MgO.

We need to calculate the no. of moles of (1.8 g) of Mg and (6.0 g) of oxygen:

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