Ask question

Ask question

All categories

antoniya [11.8K]

3 years ago

15

Together, teammates Pedro and Ricky got 2682 base hits last season. Pedro had 282 more hits than Riley. How many hits did each p

layer have?

1 answer:

pickupchik [31]3 years ago

4 0

Pedro had 1482 hits and Riley had 1200 hits.

Step-by-step explanation:

Given,

Number of base hits = 2682

Let,

Number of Pedro's hits = x

Number of Riley's hits = y

According to given statement;

x+y=2682 Eqn 1

x = y+282 Eqn 2

Putting value of x from Eqn 2 in Eqn 1

$(y+282)+y=2682\\y+282+y=2682\\2y=2682-282\\2y=2400$

Dividing both sides by 2

$\frac{2y}{2}=\frac{2400}{2}\\y=1200$

Putting y=1200 in Eqn 2

$x=1200+282\\x=1482$

Pedro had 1482 hits and Riley had 1200 hits.

Keywords: linear equation, substitution method

Learn more about substitution method at:

#LearnwithBrainly

You might be interested in

Monyne Phillips three coins. What is the probability that the first second and third Cornwall in the same way (either all heads

nasty-shy [4]

Answer:

1 in 8 chance.

Step-by-step explanation:

When a coin flips is has two outcomes: heads or tails, obviously.

Whenever you have a 50/50 probability, in this case a coin, every time you add another coin the amount of outcomes squares, or multiplies by the number of outcomes, and since we are using a coin, two. To reiterate, say we were using a die, a die is a cube, a six sided shape, so there are six outcomes. The chances of getting all sixes with one die is 1 in 6. Add another die and try to get all sixes, the chances become 1 in 36. We got this by multiplying our out comes by our outcomes

1 coin: 2 outcomes

2 coins: 4 outcomes

3 coins: 8 outcomes

Another thing:

Don't be fooled by questions being specific by saying "all heads" or "all tails"...

This is a wording trick, no matter the outcome, the chances will always be equal.

Good luck :)

8 0

3 years ago

Which is the quotient of 17. 51 +3.4?

myrzilka [38]

Answer:

5.15

Step-by-step explanation:

17.51 / 3.4 = 5.15

7 0

3 years ago

Read 2 more answers

Pleaseeeeeee helppppl asap

cluponka [151]

Answer:

37

Step-by-step explanation:

Let's use the rule GEMDAS (Grouping, Exponents, Multiply, Divide, Add, Subtract) from left to right. Therefore, we will simplify the equation in the parentheses. $2^{3} = 8. (1-8= -7)$ . -(-7) creates a double negative, deeming the 7 positive, because when there is two negatives the number will turn into a positive. $7^{2}$ = 49, -3 x 4= -12. Therefore the final form of the equation will be 49 - 12 = 37.

Let me know if there are mistakes.

7 0

2 years ago

The automatic opening device of a military cargo parachute has been designed to open when the parachute is 185 m above the groun

agasfer [191]

Answer:

0.0193 = 1.93% probability that there is equipment damage to the payload of at least one of five independently dropped parachutes.

Step-by-step explanation:

For each parachute, there are only two possible outcomes. Either there is damage, or there is not. The probability of there being damage on a parachute is independent of any other parachute, which means that the binomial probability distribution is used to solve this question.

To find the probability of damage on a parachute, the normal distribution is used.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Probability of a parachute having damage.

The opening altitude actually has a normal distribution with mean value 185 and standard deviation 32 m, which means that $\mu = 185, \sigma = 32$

Equipment damage will occur if the parachute opens at an altitude of less than 100 m, which means that the probability of damage is the p-value of Z when X = 100. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{100 - 185}{32}$

$Z = -2.66$

$Z = -2.66$ has a p-value of 0.0039.

What is the probability that there is equipment damage to the payload of at least one of five independently dropped parachutes?

0.0039 probability of a parachute having damage, which means that $p = 0.0039$

5 parachutes, which means that $n = 5$

This probability is:

$P(X \geq 1) = 1 - P(X = 0)$

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{5,0}.(0.0039)^{0}.(0.9961)^{5} = 0.9807$

Then

$P(X \geq 1) = 1 - P(X = 0) = 1 - 0.9807 = 0.0193$

0.0193 = 1.93% probability that there is equipment damage to the payload of at least one of five independently dropped parachutes.

5 0

3 years ago

Pls help meeeeeeee pls pls pls

Rom4ik [11]

Answer:

D. $\frac{4x^{2} \sqrt{29}}{29}$

Step-by-step explanation:

Given the expression:

$\frac{40x^{2} \sqrt{x^{12} } }{10x^{2} \sqrt{29x^{8} } }$

divide by the common factor to have;

$\frac{4\sqrt{x^{12} } }{\sqrt{29x^{8} } }$ = $\frac{4(x^{12}) ^{\frac{1}{2} } }{(29x^{8}) ^{\frac{1}{2} } }$

= $\frac{4x^{6} }{\sqrt{29}x^{4} }$

= $\frac{4x^{2} }{\sqrt{29} }$

Rationalize the denominator, we have;

$\frac{4x^{2} }{\sqrt{29} }$ x $\frac{\sqrt{29} }{\sqrt{29} }$

So that,

$\frac{4x^{2} \sqrt{29} }{29}$

Thus,

$\frac{40x^{2} \sqrt{x^{12} } }{10x^{2} \sqrt{29x^{8} } }$ = $\frac{4x^{2} \sqrt{29} }{29}$

The correct option is D.

5 0

3 years ago