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Troyanec [42]
3 years ago
8

I need help with number seven please

Mathematics
1 answer:
Flura [38]3 years ago
3 0
3/8 ÷ 3/4
4/8 = 1/2
the sloth moves 1/2 a foot per minute
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Edg vector operations, any help appreciated!
viktelen [127]

\quad \huge \quad \quad \boxed{ \tt \:Answer }

\qquad \tt \rightarrow \: Add \:\: -6 \hat i - 6\hat j \:\:with \:\; Vector \:\; c

____________________________________

\large \tt Solution  \: :

Vector d can be represented as :

\qquad \tt \rightarrow \:  - 2 \hat i - 2 \hat j

Vector c can be represented as :

\qquad \tt \rightarrow \:  4 \hat i + 4\hat j

we have to create vector d from vector c

So, let's assume a vector x, such that sum of vector x and vector c equals to vector d

\qquad \tt \rightarrow \: x + ( 4 \hat i + 4 \hat j) =  - 2 \hat i  - 2 \hat j

\qquad \tt \rightarrow \: x  = -  ( 4 \hat i + 4 \hat j)   - 2 \hat i  - 2 \hat j

\qquad \tt \rightarrow \: x  = (-   4 \hat i  - 2 \hat  i)  + (  - 4 \hat j  - 2 \hat j)

\qquad \tt \rightarrow \: x  = - 6 \hat  i    -6 \hat j

Henceforth, in order to get vector d, we need to add (-6i - 6j) in vector c

Answered by : ❝ AǫᴜᴀWɪᴢ ❞

8 0
2 years ago
What is m∠2?<br> What is m∠1?
Greeley [361]

Answer:

<2 = 75

<1 = 105

Step-by-step explanation:

<2 and 75 are alternate interior angles and since the lines are parallel, they are equal

<2 = 75

<2 + <1 = 180    since the angles form a line

75+ <1 = 180

Subtract 75 from each side

<1 = 180-75

<1 = 105

6 0
3 years ago
Read 2 more answers
If the mean weight of 4 backfield members on the football team is 221 lb and the mean weight of the 7 other players is 202 lb, w
MatroZZZ [7]

Let x_1, x_2, x_3, x_4, x_5, x_6, x_7, x_8, x_9, x_{10}, x_{11} be the weight of i-th player.

1. If the mean weight of 4 backfield members on the football team is 221 lb, then

\dfrac{x_1+x_2+x_3+x_4}{4}=221\ lb.

2. If the mean weight of the 7 other players is 202 lb, then

\dfrac{x_5+x_6+x_7+x_8+x_9+x_{10}+x_{11}}{7}=202\ lb.

3. From the previous statements you have that

x_1+x_2+x_3+x_4=221\cdot 4=884 \lb,\\ \\x_5+x_6+x_7+x_8+x_9+x_{10}+x_{11}=202\cdot 7=1414\ lb.

Add these two equalities and then divide by 11:

x_1+x_2+x_3+x_4+x_5+x_6+x_7+x_8+x_9+x_{10}+x_{11}=884+1414=2298\ lb,\\ \\\dfrac{x_1+x_2+x_3+x_4+x_5+x_6+x_7+x_8+x_9+x_{10}+x_{11}}{11}=\dfrac{2298}{11}=208\dfrac{10}{11}\ lb.

Answer: the mean weight of the 11-person team is 208\dfrac{10}{11}\ lb.

4 0
3 years ago
39. Suppose A is an m n matrix with the property that for all b in Rm the equation Ax D b has at most one solution. Use the defi
Anna [14]

Answer: trivial solution is the only solution to Ax = 0, therefore columns must be linearly independent.

Step-by-step explanation: Recall that the columns of A are linearly independent if and only Ax = 0 had only the trivial solution. Since Ax = b has at most one solution, therefore the only solution to Ax = 0 is the trivial solution and the column vectors must be linearly independent.

5 0
3 years ago
Jessica is baking a cake. The recipe says that she has to mix 96 grams of sugar to the flour. Jessica knows that 1 cup of this p
timama [110]
Jessica should add more sugar to the flour. One over two of a cup of sugar is 64 grams. 64 grams is about 32 grams less than the amount needed
6 0
3 years ago
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