How to I rewrite 3a+6b=d in terms of b and d

Mathematics

1 answer:

masha68 [24]3 years ago

6 0

In terms of b-----
3a+6b=d
6b=d-3a
b=d-3a/6

In terms of d-------
3a+6b=d
d=3a+6b

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Suppose Kaitlin places $6500 in an account that pays 12% interest compounded each year.

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$\bf ~~~~~~ \textit{Compound Interest Earned Amount \underline{for 2 years}} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$6500\\ r=rate\to 12\%\to \frac{12}{100}\dotfill &0.12\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{annually, thus once} \end{array}\dotfill &1\\ t=years\dotfill &2 \end{cases}$

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One dozen eggs is 48 eggs. Altogether that costs 40 dollars. If six of the eggs were broken then the money wasted would be 5 dollars.

The reason that it is 5 dollars is becuase it takes 10 to buy 12 eggs, and half of that is 6. So divide both 12 and 10 (separately) and you get 5 dollars for 6 eggs.

To get the percent you must divide 5 by 40.

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