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3 years ago

How to I rewrite 3a+6b=d in terms of b and d

Mathematics

1 answer:

masha68 [24]3 years ago

6 0

In terms of b-----
3a+6b=d
6b=d-3a
b=d-3a/6

In terms of d-------
3a+6b=d
d=3a+6b

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Answer:

Part 1) solution {(-5,8),(3,0)} ----> $y+12=x^{2}+x$ and $x+y=3$

Part 2) No solutions ----> $y-15=x^{2}+4x$ and $x-y=1$

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Step-by-step explanation:

Part 1) we have

$y+12=x^{2}+x$ ----> equation A

$x+y=3$ ----> equation B

Solve by graphing

Remember that the solution of the system of equations is the intersection point both graphs

The solution are the points (-5,8) and (3,0)

see the attached figure N 1

Part 2) we have

$y-15=x^{2}+4x$ ----> equation A

$x-y=1$ ----> equation B

Solve by graphing

Remember that the solution of the system of equations is the intersection point both graphs

The system has no solutions, because there is no point of intersection between the two graphs

see the attached figure N 2

Part 3) we have

$y+5=x^{2}-3x$ ----> equation A

$2x+y=1$ ----> equation B

Solve by graphing

Remember that the solution of the system of equations is the intersection point both graphs

The solution are the points (-2,5) and (3,-5)

see the attached figure N 3

Part 4) we have

$y-6=x^{2}-3x$ ----> equation A

$x+2y=2$ ----> equation B

Solve by graphing

Remember that the solution of the system of equations is the intersection point both graphs

The system has no solutions, because there is no point of intersection between the two graphs

see the attached figure N 4

Part 5) we have

$y-17=x^{2}-9x$ ----> equation A

$-x+y=1$ ----> equation B

Solve by graphing

Remember that the solution of the system of equations is the intersection point both graphs

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see the attached figure N 5

Part 6) we have

$y-15=-x^{2}+4x$ ----> equation A

$x+y=1$ ----> equation B

Solve by graphing

Remember that the solution of the system of equations is the intersection point both graphs

The solution are the points (-2,3) and (7,-6)

see the attached figure N 6

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