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3 years ago

What is the mean absolute deviation of 7

Mathematics

1 answer:

nikitadnepr [17]3 years ago

6 0

Answer:

Step-by-step explanation:

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PLEASEEEEE HELP WITH THIS??!!!! According to the diagram, what is the altitude?

snow_tiger [21]

X^2 + 400^2 = 500^2
solve for x.
x^2=25,000-16,000
x^2= 9,000
x=
$x = \sqrt{9000}$
x= 94.86m

5 0

3 years ago

Read 2 more answers

Seventy-five balls numbered from 1 to 75 are placed in an urn. One ball is randomly drawn from the urn. What is the probability

kramer

75-31= 44
44/75= 0.58666 or 58.7%

Subtract 31 from 75 since we're figuring out greater than or "equal to" we want to include the number 32 in our equation. If it was only "greater than" 32 then we'd subtract 32 from 75. Then you divide that number(44) by 75, which is all the possible outcomes you could have in this scenario. Move the decimal two places to the right to make it a percentage and you've got your answer.

6 0

3 years ago

The "Mr. Brust Dance School of Fine Ballet" charges $24 per dass and a one-time registration fee $150 A student paid a total of

irinina [24]

Answer- 28 classes

Step-by-step explanation:

822-150= 672 672/24 = 28

5 0

3 years ago

Read 2 more answers

1.) Find the length of the arc of the graph x^4 = y^6 from x = 1 to x = 8.

xxTIMURxx [149]

First, rewrite the equation so that y is a function of x :

$x^4 = y^6 \implies \left(x^4\right)^{1/6} = \left(y^6\right)^{1/6} \implies x^{4/6} = y^{6/6} \implies y = x^{2/3}$

(If you were to plot the actual curve, you would have both $y=x^{2/3}$ and $y=-x^{2/3}$ , but one curve is a reflection of the other, so the arc length for 1 ≤ x ≤ 8 would be the same on both curves. It doesn't matter which "half-curve" you choose to work with.)

The arc length is then given by the definite integral,

$\displaystyle \int_1^8 \sqrt{1 + \left(\frac{\mathrm dy}{\mathrm dx}\right)^2}\,\mathrm dx$

We have

$y = x^{2/3} \implies \dfrac{\mathrm dy}{\mathrm dx} = \dfrac23x^{-1/3} \implies \left(\dfrac{\mathrm dy}{\mathrm dx}\right)^2 = \dfrac49x^{-2/3}$

Then in the integral,

$\displaystyle \int_1^8 \sqrt{1 + \frac49x^{-2/3}}\,\mathrm dx = \int_1^8 \sqrt{\frac49x^{-2/3}}\sqrt{\frac94x^{2/3}+1}\,\mathrm dx = \int_1^8 \frac23x^{-1/3} \sqrt{\frac94x^{2/3}+1}\,\mathrm dx$

Substitute

$u = \dfrac94x^{2/3}+1 \text{ and } \mathrm du = \dfrac{18}{12}x^{-1/3}\,\mathrm dx = \dfrac32x^{-1/3}\,\mathrm dx$

This transforms the integral to

$\displaystyle \frac49 \int_{13/4}^{10} \sqrt{u}\,\mathrm du$

and computing it is trivial:

$\displaystyle \frac49 \int_{13/4}^{10} u^{1/2} \,\mathrm du = \frac49\cdot\frac23 u^{3/2}\bigg|_{13/4}^{10} = \frac8{27} \left(10^{3/2} - \left(\frac{13}4\right)^{3/2}\right)$

We can simplify this further to

$\displaystyle \frac8{27} \left(10\sqrt{10} - \frac{13\sqrt{13}}8\right) = \boxed{\frac{80\sqrt{10}-13\sqrt{13}}{27}}$

7 0

3 years ago

Find the vertex of f(x) = |x – 5| + 10

Novay_Z [31]

The vertex will end up landing on (5,10)

6 0

3 years ago