The correct answer is 33 days
Answer:
The value is
Step-by-step explanation:
From the question we are told that
The sample mean is ![\= x = 9 \ ounce](https://tex.z-dn.net/?f=%5C%3D%20x%20%20%3D%20%209%20%5C%20%20ounce)
The sample size is n = 25
The standard deviation is ![\sigma = 3 \ ounce](https://tex.z-dn.net/?f=%5Csigma%20%3D%20%203%20%5C%20ounce)
Given that the sample size is not large enough i.e n< 30 we will make use of the student t distribution table
From the question we are told the confidence level is 99.7% , hence the level of significance is
=>
Generally the degree of freedom is ![df = n- 1](https://tex.z-dn.net/?f=df%20%3D%20%20n-%201)
=> ![df = 25 - 1](https://tex.z-dn.net/?f=df%20%3D%20%2025%20-%201)
=>
Generally from the student t distribution table the critical value of
at a degree of freedom of
is
Generally the margin of error is mathematically represented as
=>
=>
Gnerally the upper control chart limit for 99.7% confidence is mathematically represented as
![UCL = \= x + E](https://tex.z-dn.net/?f=UCL%20%20%3D%20%20%5C%3D%20x%20%20%2B%20E)
=>
=>
3 drops : 4 pints = x drops : 16 pints
3drops/4pints = x/16pints
(3drops/4pints)*16pints = x
*cancel pints unit*
(3drops/4)*16 = x
(16*3)drops/4 = x
48 drops / 4 = x
12 drops = x (ANSWER)
Answer:
The mean is 39
The median is 42
Step-by-step explanation:
The median is the best measure of center for the above data because half of the values are less than the median and half of the values are more than the median. It's probably the best measure of center to use in a skewed distribution.
The measure of variability is the range because is the simplest measure of variability to calculate but can be misleading if the dataset contains extreme values.
The variability is 67.25
This is how I did it