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Sergeeva-Olga [200]
3 years ago
12

PLEASE HELP. TAKE AT HOME TEST. if u = LN5 and v = LN2, write LN8/15 in terms of u and v. (8/15 is 8 over 25)

Mathematics
1 answer:
astra-53 [7]3 years ago
8 0

Answer:

\ln( \frac{8}{25} )  = 3v  -  2u

Step-by-step explanation:

We have that

u=  \ln(5)

and

v =  \ln2

This implies that;

5 =  {e}^{u}

and

2 =  {e}^{v}

Now find and expresion for

\ln( \frac{8}{25} )

Which is

\ln( \frac{8}{25} )  =  ln(8)  -  ln(25)

\ln( \frac{8}{25} )  =  ln( {2}^{3} )  -  ln(  {5}^{2} )

\ln( \frac{8}{25} )  = 3 ln( {2} )  -  2ln(5)

\ln( \frac{8}{25} )  = 3v  -  2u

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What is the slope of line segment AB?<br> A) 2/3<br> B) 3/4<br> C) 4/3<br> D) -3/4
Lunna [17]

For this case we have that by definition, the slope of a line is given by:

m = \frac {y_ {2} -y_ {1}} {x_ {2} -x_ {1}}

Where:

(x_ {1}, y_ {1})and (x_ {2}, y_ {2})are two points through which the line passes.

According to the image we have:

(x_ {1}, y_ {1}): (-5,3)\\(x_ {2}, y_ {2}): (3, -3)

Substituting we have:

m = \frac {-3-3} {3 - (- 5)} = \frac {-6} {3 + 5} = \frac {-6} {8} = - \frac {3} {4}

Thus, the slope of the line is:

m = - \frac {3} {4}

Answer:

m = - \frac {3} {4}

3 0
3 years ago
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I need help fast please
Mademuasel [1]
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5 0
2 years ago
Each side of a square calendar is 19 inches long. What is the calendar's perimeter?
liberstina [14]

Answer:

a square has 4 sides each of those sides is 19in long perimeter is all around the square so you would add 19+19+19+19=79in

6 0
3 years ago
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Pls solve part b) iii thanks
Viktor [21]

The bearing of the tree from Q is 296.565°

<h3>How to determine the height of the tree?</h3>

The figure that illustrates the bearing and the distance is added as an attachment

The given parameters are:

Base of the tree, b = 50 meters

Angle (x) = 32 degrees

Calculate the height (h) of the tree using:

tan(x) = height/base

So, we have:

tan(32°) = h/50

Make h the subject

h= 50 × tan(32°)

Evaluate

h = 31.24

Hence, the height of the tree is 31.24 meters

<h3>How to determine the distance between Q and the base of the tree?</h3>

The distance (d) between Q and the base of the tree

This is calculated using the following Pythagoras theorem

d = √(100² + 50²)

Evaluate

d = 111.80

Hence, the distance between Q and the base of the tree is 111.80 meters

<h3>How to determine the angle of elevation?</h3>

The angle of elevation (x) using the following tangent trigonometric ratio

tan(x) = h/d

This gives

tan(x) = 31.24/111.80

Evaluate the quotient

tan(x) = 0.2794

Take the arc tan of both sides

x = 15.61

<h3>The bearing of the tree from Q </h3>

This is calculated using:

Angle of bearing = 270 + arctan(50/100)

Evaluate the arc tan

Angle of bearing = 270 + 26.565

Evaluate the sum

Angle of bearing = 296.565

Hence, the bearing of the tree from Q is 296.565 degrees

Read more about bearings at:

brainly.com/question/24142612

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4 0
2 years ago
The sum of two numbers is 30. the first number is twice the second number. what are the numbers?
Fudgin [204]
Let the numbers be x and y.

by the first statement of the question, we get , x + y = 30.,,..(1)

by the second satement, we get , x = y+ y => x=2y... (2)

from equation (2), let us put the value of x in equation (1),
x + y = 30
=> 2y + y = 30
=> 3y = 30
=> y =30/3
=> y = 10

and x=2y => x = 2*10 = 20

in short, the numbers are 10 and 20

 
3 0
3 years ago
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