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Sergeeva-Olga [200]
3 years ago
12

PLEASE HELP. TAKE AT HOME TEST. if u = LN5 and v = LN2, write LN8/15 in terms of u and v. (8/15 is 8 over 25)

Mathematics
1 answer:
astra-53 [7]3 years ago
8 0

Answer:

\ln( \frac{8}{25} )  = 3v  -  2u

Step-by-step explanation:

We have that

u=  \ln(5)

and

v =  \ln2

This implies that;

5 =  {e}^{u}

and

2 =  {e}^{v}

Now find and expresion for

\ln( \frac{8}{25} )

Which is

\ln( \frac{8}{25} )  =  ln(8)  -  ln(25)

\ln( \frac{8}{25} )  =  ln( {2}^{3} )  -  ln(  {5}^{2} )

\ln( \frac{8}{25} )  = 3 ln( {2} )  -  2ln(5)

\ln( \frac{8}{25} )  = 3v  -  2u

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Answer:

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Step-by-step explanation:

It is always a good idea to start by defining variables in such a problem. Here, we can let x represent the number of calling minutes, and y represent the number of data minutes. The the total number of minutes used is ...

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The total of charges is the sum of the products of charge per minute and minutes used:

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We can eliminate the x-variable in these equations by multiplying the first by -7 and the second by 20, then adding the result.

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  -7x -7y +7x +8y = -595 +620 . . . . eliminate parentheses

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3 years ago
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How do I use the arc length to find the circumference ?
Mashutka [201]
<span>arc length   =   circumference • [central angle (degrees) ÷ 360]

Solving this equation for circumference:
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</span>circumference = 12 / <span><span>0.2361111111 </span>
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Source:
http://www.1728.org/radians.htm


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A and C is the answer

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