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lbvjy [14]
3 years ago
5

PLEASE HELPPP Will Give brainliest if it help :) The question : You are at an amusement park with your friend. You spend $11.00

on a stuffed animal
for your little brother. Then you and your friend ride the roller coaster several times
together for $4.00 each. Write a system of linear equations that represents this
situation. Will you and your friend spend the same amount of money? Explain.
Mathematics
1 answer:
sattari [20]3 years ago
5 0

Answer:

y= 4x + 11   and no.

Step-by-step explanation:

Because you spent the 11 dollars extra and rode the rides meanwhile your friend only went on the rides. If (x) equals the amount of rides and (y) means the total amount. Then your friends equation with be y= 4x. But, you already spent 11 dollars additionally so therefore your equation with be y=4x + 11.

I hope this helped.

Friend  y=4x

You  y=4x + 11

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In the expansion of (1/ax +2ax^2)^5 the coefficient of x is five. Find the value of the constant a.
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Answer:

80x⁴

Step-by-step explanation:

(\frac{1}{ax} + 2ax^2)^5 = 5C_0(\frac{1}{ax})^5(2ax^2)^0 + 5C_1(\frac{1}{ax})^4(2ax^2)^1 + 5C_2(\frac{1}{ax})^3 (2ax^2)^2

                           + 5C_3 (\frac{1}{ax})^2(2ax^2)^3 + 5C_4(\frac{1}{ax})^1(2ax^2)^4 + 5C_5(\frac{1}{ax})^0(2ax^2)^5

5C_0(\frac{1}{ax})^5(2ax^2)^0  =1 \times (\frac{1}{ax})^5 \times 1 = \frac{1}{a^5x^5}\\\\5C_1(\frac{1}{ax})^4(2ax^2)^1  = 5 \times (\frac{1}{ax})^4 \times (2ax^2)^1 = 10 ax^2 \times \frac{1}{a^4x^4} = \frac{10}{a^3x^2}\\\\5C_2 (\frac{1}{ax})^3 (2ax^2)^2= 10 \times (\frac{1}{ax})^3 \times (2ax^2)^2 = 10 \times \frac{1}{a^3x^3} \times 4a^2x^4 = \frac{40x}{a}\\\\5C_3 (\frac{1}{ax})^2 (2ax^2)^3 = 10 \times (\frac{1}{ax})^2 \times (2ax^2)^3 = 10 \times \frac{1}{a^2x^2} \times 8a^3 x^6 = 80ax^4\\\\

5C_4(\frac{1}{ax})^1(2ax^2)^4 = 5 \times \frac{1}{ax} \times 16a^4x^8 = 80a^3x^7\\\\5C_5(\frac{1}{ax})^0(2ax^2)^5 = 1 \times 1 \times 32a^5x^{10}

The fourth term of the expansion has the constant a,

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