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Mariana [72]
4 years ago
11

What equals 42 & 50 in multiplication Thanks So Much!!!!!!!

Mathematics
2 answers:
Mars2501 [29]4 years ago
5 0
42 = 7 x 6
42 = 21 x 2
42 = 3.5 x 12

50 = 25 x 2
50 = 5 x 10

Paha777 [63]4 years ago
4 0
5 × 10 = 50

6 × 7 = 42
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Write the fraction 8/9 as a percent round to the nearest hundredth of a percent were necessary?
Flura [38]

Answer:

A

Step-by-step explanation:

To turn a fraction into a percent, you divide the numerator by the denominator.

8 divided by 9 = .8 repeated

To turn it into a percent, you move the decimal to the right 2 spaces.

.8 turns into 88.8 repeated

Then you round to the nearest hundredth

88.8 repeated rounds to 88.89.

7 0
3 years ago
What is the domain of the function f(x) = 2x + 5?
alukav5142 [94]

There is no value that x cannot be for linear equations.

Thus, the domain is ALL REAL NUMBERS.

CHOICE B.

8 0
3 years ago
A company manufactures and sells shirts. The daily profit the company makes
Rom4ik [11]

Answer:

f(-5) = -150

Meaning: If the company sells -5 shirts, they would make a profit of -150 dollars. This interpretation of loss in the context of the problem

f(7) = -30

Meaning: If the company sells 7 shirts, they would make a profit of -30 dollars. This interpretation of loss in the context of the problem

f(10.5) = 5

Meaning: If the company sells 10.5 shirts, they would make a profit of 5 dollars. This interpretation of profit in the context of the problem

Step-by-step explanation:

Given

f(x) = 10x - 100

Required

Fill in the gap

f(-5) = 10 * -5 -100

f(-5) = -50 -100

f(-5) = -150

f(7) = 10 * 7 - 100

f(7) = 70 - 100

f(7) = -30

f(10.5) = 10 * 10.5 - 100

f(10.5) = 105 - 100

f(10.5) = 5

5 0
3 years ago
A right-angled triangle has shorter side lengths exactly c^2-b^2 and 2bc units respectively, where b and c are positive real num
yKpoI14uk [10]

Answer: hypotenuse = c^{2} + b^{2}

Step-by-step explanation: Pythagorean theorem states that square of hypotenuse (h) equals the sum of squares of each side (s_{1},s_{2}) of the right triangle, .i.e.:

h^{2} = s_{1}^{2} + s_{2}^{2}

In this question:

s_{1} = c^{2}-b^{2}

s_{2} = 2bc

Substituing and taking square root to find hypotenuse:

h=\sqrt{(c^{2}-b^{2})^{2}+(2bc)^{2}}

Calculating:

h=\sqrt{c^{4}+b^{4}-2b^{2}c^{2}+(4b^{2}c^{2})}

h=\sqrt{c^{4}+b^{4}+2b^{2}c^{2}}

c^{4}+b^{4}+2b^{2}c^{2} = (c^{2}+b^{2})^{2}, then:

h=\sqrt{(c^{2}+b^{2})^{2}}

h=(c^{2}+b^{2})

Hypotenuse for the right-angled triangle is h=(c^{2}+b^{2}) units

3 0
3 years ago
Please, help me. I'm not sure what to do.
Nezavi [6.7K]
Answer is d, its simple....
3 0
4 years ago
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