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Stels [109]
3 years ago
15

It is estimated that 4000 of the 10,000 voting residents of a town are against a new sales tax. If 15 eligible voters are select

ed at random and asked their opinion, what is the probability that at most 7 favor the new tax?
Mathematics
1 answer:
Alenkasestr [34]3 years ago
3 0

Answer:

The probability that at most 7 favor the new tax is 0.7869

Step-by-step explanation:

Total number of voting resident = 10000

number of voting resident against new sales tax = 4000

therefore probability of choosing a voting resident against new sales tax = 4000/10000 = 0.4

If 15 eligible voters are selected at random and asked their opinion, what is the probability that at most 7 favor the new tax

Using binomial,

number of selected voters(n) =15,

p=0.4

P(x<=0.7) = binomialcdf(15, 0.4, 7)

Using your calculator

P(x<=0.7) = binomialcdf(15, 0.4, 7) = 0.7869

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a. 0.76

b. 0.23

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Step-by-step explanation:

a. p(AUBUC)= P(A)+P(B)+P(C)-P(AnB)-P(AnC)-P(BnC)+P(AnBnC)

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c. P(B/A)= P(AnB)/P(A)

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e. P((AnB)/C))= P((AnB)nC)/P(C)

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                     =0.07/0.2= 0.35

f. P((AUB)/C)= P((AUB)nC)/P(C)

                    =(P(AnC) U P(BnC))/P(C)

                     =(0.11+0.1)/0.2

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