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Dmitry [639]
3 years ago
8

How am I going to estimate that if I don't know the size of the door? Heeeelp please

Mathematics
2 answers:
vitfil [10]3 years ago
7 0

An average door is about six feet tall. 9.4 meters is about 30 feet.

30 ÷ 6 = 5

I think the whale will be about 5 doors long.

(This is a weird problem.)

wolverine [178]3 years ago
3 0

C) 5. Doors are about 6 feet and 9.4m is roughly the equivalent of 30 feet. So 6 x 5 = 30

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devlian [24]
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3 years ago
Can someone please help me figure this out, thanks!
AURORKA [14]

Answer:

The set of numbers that could not represent the three sides of a right triangle are;

{9, 24, 26}

Step-by-step explanation:

According to Pythagoras's theorem, when the lengths of the three sides of a right triangle includes two legs, 'x', and 'y', and the hypotenuse side 'r', we have;

r² = x² + y²

Where;

r > x, r > y

Therefore, analyzing the options using the relationship between the numbers forming the three sides of a right triangle, we have;

Set 1;

95² = 76² + 57², therefore, set 1 represents the three sides of a right triangle

Set 2;

82² = 80² + 18², therefore, set 2 represents the three sides of a right triangle

Set 3;

26² = 24² + 9², therefore, set 3 could not represent the three sides of a right triangle

Set 4;

39² = 36² + 15², therefore, set 4 represents the three sides of a right triangle

4 0
3 years ago
In remodeling a kitchen, a builder decides to place a splash-guard behind the sink consisting of eight 6-inch-square ceramic til
oksano4ka [1.4K]

Answer:

(a) 0.4242

(b) 0.0707

Step-by-step explanation:

The total number of ways of selecting 8 herbs from 12 is

\binom{12}{8}=495

(a) If 2 herbs are selected, then there are 8 - 2 = 6 herbs to be selected from 12 - 8 = 10. The number of ways of the selection is then

\binom{10}{6}= 210

Note that this is the number of ways that both are included. We would have multiplied by 2! if any of them were to be included.

The probability = \dfrac{210}{495}=0.4242

(b) If 5 herbs are selected, then there are 8 - 5 = 3 herbs to be selected from 12 - 5 = 7. The number of ways of the selection is then

\binom{7}{3}= 35

This is the number of ways that both are included. We would have multiplied by 5! if any of them were to be included. In that case, our probability will exceed 1; this implies that certainly, at least, one of them is included.

The probability = \dfrac{35}{495}=0.0707

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3 years ago
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5 0
3 years ago
Read 2 more answers
Do any of you get this question? Please help!
Alexxandr [17]
Honestly i just wanted to try this question since ive never seen it but i dont rlly know if i did it right at all

I equaled GH, HI, and GI together to get y

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GH, HI, and GI all equaled -11

if you kind of know how to do the question maube you could correct me from there but otherwise dont take my word for it completely

4 0
3 years ago
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