Calculate the volume change for respiration in the dark. As you already saw from earlier questions, oxygen production is fairly
constant. You will not need to calculate the individual volume changes. Just subtract the original volume at 00:00:00 from the final reading at 00:02:00. Record your answer for use in a later question. Note: depending on when you started the timer there is a range of possible answers. Pick the answer that is closest to yours. What was the volume change for respiration in the dark?
1 answer:
Answer:
-1.9mL/min
Explanation:
The rate of O₂ production can be calculated by the formula
= ( Final volume - initial volume)/time(min).
From the graph provided and attached below, the rate of O₂ production or rate of photosynthesis at light intensity of 8 is about 3.75 mL/min.
The rate of O₂ production is taken as the rate of photosynthesis. It is expected to progressively increase from light intensity 0 as light intensity increases. However, at very high light intensity, the rate slows down as water becomes limiting and the stomata closes in order to conserve water.
Question in order
Experiment 2: Respiration in the Dark
Calculate the volume change for respiration in the dark. As you already saw from earlier questions,
oxygen production is fairly constant. You will not need to calculate the individual volume changes.
Just subtract the original volume at 00:00:00 from the final reading at 00:02:00. Record your answer
for use in a later question.
<em>Note: depending on when you started the timer there is a range of possible answers. Pick the answer that is closest to this</em>
What was the volume change for respiration in the dark?
Correct answer:
-1.9 mL/min
You might be interested in
Answer:
The correct model is D.
Note: The first attachment below shows the different models. The second attachment shows the correct structural model of the water molecule.
Explanation:
A water molecule is composed of one atom of oxygen and two atoms of hydrogen.
A water molecule is polar, i.e. it contains positively and negatively opposite ends. The polar nature of the water molecule is due to strong electronegativity of oxygen which results in an uneven sharing of the bonding electrons between oxygen and hydrogen. The oxygen atom attracts the shared electrons more to itself, thereby, it acquires a partial negative charge, while the hydrogen atoms acquire a partial positive charge.
The bond angle between the oxygen and hydrogen atoms is approximately 105°. Therefore, from the first attachment below, the correct model for the water molecule is D.
