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3 years ago

12

Is this a function and what's the domain and range. thanks!

2 answers:

kiruha [24]3 years ago

8 0

This is not a function. Why not? Because it fails the vertical line test. The input x = 3 leads to more than one output (eg: y = 1, y = 2, y = 3). A function is only possible if each input leads to exactly one output.

Domain = {3} so basically x is only allowed to be x = 3.

Range = set of y values such that y is between 1 and 5 (including both endpoints. As a compound inequality, the range is written as $1 \le y \le 5$

fenix001 [56]3 years ago

6 0

The domain is the x coordinates (input) and the Y is the range , (output). Hope this helps. :)

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The perimeter of a 5-sided figure is 45.56 meters. Two of the sides have the same length. The sum of the other three side length

balandron [24]

10.68 each for the 2 same length sides. The total of the 5 sides is 45.56 less the 3 sides which total 24.2 leaves 21.36 remaining for the 2 equal length sides. So divide 21.36 by 2 = 10.68
(45.56 - 24.2)/2 = 10.68

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2 years ago

Read 2 more answers

Please help :( im struggling

Paha777 [63]

Answer:

a= 9/4

Step-by-step explanation:

2m^(5/2)/m^(1/4)

2m^(5/2 -1/4)

2m^(9/4)

Hope you find this helpful <3

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3 years ago

Lauren has 43 flowers she has 16 fewer flowers than gabriel how many flower does gabriel have

WARRIOR [948]

Answer:

Step-by-step explanation:

Gabrielhs 59 flowers because 43 + 16= 59.

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2 years ago

Read 2 more answers

2. In how many ways can 3 different novels, 2 different mathematics books and 5 different chemistry books be arranged on a books

insens350 [35]

The number of ways of the books can be arranged are illustrations of permutations.

When the books are arranged in any order, the number of arrangements is 3628800
When the mathematics book must not be together, the number of arrangements is 2903040
When the novels must be together, and the chemistry books must be together, the number of arrangements is 17280
When the mathematics books must be together, and the novels must not be together, the number of arrangements is 302400

The given parameters are:

$\mathbf{Novels = 3}$

$\mathbf{Mathematics = 2}$

$\mathbf{Chemistry = 5}$

<u />

<u>(a) The books in any order</u>

First, we calculate the total number of books

$\mathbf{n = Novels + Mathematics + Chemistry}$

$\mathbf{n = 3 + 2 + 5}$

$\mathbf{n = 10}$

The number of arrangement is n!:

So, we have:

$\mathbf{n! = 10!}$

$\mathbf{n! = 3628800}$

<u>(b) The mathematics book, not together</u>

There are 2 mathematics books.

If the mathematics books, must be together

The number of arrangements is:

$\mathbf{Maths\ together = 2 \times 9!}$

Using the complement rule, we have:

$\mathbf{Maths\ not\ together = Total - Maths\ together}$

This gives

$\mathbf{Maths\ not\ together = 3628800 - 2 \times 9!}$

$\mathbf{Maths\ not\ together = 2903040}$

<u>(c) The novels must be together and the chemistry books, together</u>

We have:

$\mathbf{Novels = 3}$

$\mathbf{Chemistry = 5}$

First, arrange the novels in:

$\mathbf{Novels = 3!\ ways}$

Next, arrange the chemistry books in:

$\mathbf{Chemistry = 5!\ ways}$

Now, the 5 chemistry books will be taken as 1; the novels will also be taken as 1.

Literally, the number of books now is:

$\mathbf{n =Mathematics + 1 + 1}$

$\mathbf{n =2 + 1 + 1}$

$\mathbf{n =4}$

So, the number of arrangements is:

$\mathbf{Arrangements = n! \times 3! \times 5!}$

$\mathbf{Arrangements = 4! \times 3! \times 5!}$

$\mathbf{Arrangements = 17280}$

<u>(d) The mathematics must be together and the chemistry books, not together</u>

We have:

$\mathbf{Mathematics = 2}$

$\mathbf{Novels = 3}$

$\mathbf{Chemistry = 5}$

First, arrange the mathematics in:

$\mathbf{Mathematics = 2!}$

Literally, the number of chemistry and mathematics now is:

$\mathbf{n =Chemistry + 1}$

$\mathbf{n =5 + 1}$

$\mathbf{n =6}$

So, the number of arrangements of these books is:

$\mathbf{Arrangements = n! \times 2!}$

$\mathbf{Arrangements = 6! \times 2!}$

Now, there are 7 spaces between the chemistry and mathematics books.

For the 3 novels not to be together, the number of arrangement is:

$\mathbf{Arrangements = ^7P_3}$

So, the total arrangement is:

$\mathbf{Total = 6! \times 2!\times ^7P_3}$

$\mathbf{Total = 6! \times 2!\times 210}$

$\mathbf{Total = 302400}$

Read more about permutations at:

brainly.com/question/1216161

8 0

2 years ago

Order the number 7/4, 1.6, 1 5/8, 1.65 from least to greatest.

Debora [2.8K]

Here are the numbers from least to greatest
1.6,1.65,15/8,7/4

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3 years ago