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3 years ago

Find the product of (x + 3)(x − 3). x2 − 6x + 9 x2 + 6x + 9 x2 + 9 x2 − 9

Mathematics

2 answers:

oksian1 [2.3K]3 years ago

6 0

Find the product of (x + 3)(x − 3)

Answer:

x^2 − 9

(Took the exam)

julia-pushkina [17]3 years ago

3 0

The answer would be x^2-9

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4 years ago

Let (8,−3) be a point on the terminal side of θ. Find the exact values of cosθ, cscθ, and tanθ.

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Answer:

$\text{Cos}\theta=\frac{\text{Adjacent side}}{\text{Hypotenuse}}=\frac{x}{R}=\frac{8}{\sqrt{73}}$

$\text{Csc}\theta=-\frac{\sqrt{73}}{3}$

$\text{tan}\theta =\frac{\text{Opposite side}}{\text{Adjacent side}}=\frac{y}{x}=\frac{-3}{8}$

Step-by-step explanation:

From the picture attached,

(8, -3) is a point on the terminal side of angle θ.

Therefore, distance 'R' from the origin will be,

R = $\sqrt{x^{2}+y^{2}}$

R = $\sqrt{8^{2}+(-3)^2}$

= $\sqrt{64+9}$

= $\sqrt{73}$

Therefore, Cosθ = $\frac{\text{Adjacent side}}{\text{Hypotenuse}}=\frac{x}{R}=\frac{8}{\sqrt{73}}$

Sinθ = $\frac{\text{Opposite side}}{\text{Hypotenuse}}=\frac{y}{R}=\frac{-3}{\sqrt{73} }$

tanθ = $\frac{\text{Opposite side}}{\text{Adjacent side}}=\frac{y}{x}=\frac{-3}{8}$

Cscθ = $\frac{1}{\text{Sin}\theta}=\frac{R}{y}=-\frac{\sqrt{73}}{3}$

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4 years ago

At a college, 7 out of 10 students work either a full-time or a part-time job in addition to their studies. If 4900 students wer

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Answer:

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Step-by-step explanation:

We have a relationship between students who have a part-time job and those who do not. The ratio is 7 out of 10 students.

Then we use this relationship as a conversion factor.

If of 10 students, 7 of them have a job, then of 4900 students, how many of them have a job?

$4900 * \frac{7}{10}=3430$ students

Finally, those who do not have a job are:

$4900- 3430 = 1470$

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