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Ainat [17]
3 years ago
14

Help fastttt please!!!!! When making a pie chart for this data, what percentage of the dresses would the sector label "Blue" inc

lude? Round to the nearest percent. Show your work or explain how you got your answer please i need helppp fast

Mathematics
1 answer:
lbvjy [14]3 years ago
4 0

Answer:

14%

Step-by-step explanation:

First find the total for all the dresses.

Total = 14 + 37 + 22 + 56 + 33

Total = 162

Now you are concerned about the blue dresses.

% = (22 / 162)  * 100 = 13.58 %

Rounded to the nearest % it would be 14%

The number of degrees it would occupy in the pie chart would be 360 * 14/100 = 49 degrees.

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32+b=54 when b = 9 <br> what is the answer
Strike441 [17]

Step-by-step explanation:

I have two step

step 1

32+b=54

32+9=54

41=54

you divide both side by 41 and the answer is 1 and 1

step two

32+b=54

b=54-32

9=22

you divide both side by 9 and the answer is 2,44

7 0
2 years ago
Urgent!! I will give brainiest to right answer
Over [174]

Answer:

1) option c

2) option d

3) option a

4) option a

5) option c

Step-by-step explanation:

1. Given that in ΔRST, ∠R=63°, ∠T=90° and so  ∠S=27°

Also, cosec=hyotenuse/opposite side

Given RS=23 and ST=10.4

So, cosec27=RS/RT=23/RT

sec=hypotenuse/adjacent side

sec27=RS/ST=23/10.4

And cot=adjacent/opposite side

So, cot63=RT/ST=RT/10.4

2. formula:- sinθ=opposite side/hypotenuse

                     cosecθ=hypotenuse/opposite side

∴ sinθ *cosecθ = (opposite side/hypotenuse) * (hypotenuse/opposite side) = 1

3. Formula :- tan(360-θ) = -tanθ

∴ tan(300) = tan(360-60) = -tan30°

tan30° = √3

∴tan300° = -√3

4.

5. sinθ= opposite side/hypotenuse

cosecθ = hypotenuse/opposite side

∴ cosecθ = 1/sinθ

Given sinθ = 0.3090

∴ cosecθ = 1/0.3090 = 3.2362

8 0
3 years ago
Write a congruence statement for the pair of triangles. Name the postulate it theorem that justifies your statement.
mezya [45]

Answer:

B

Step-by-step explanation:

4 0
2 years ago
Simplify (−5p^3)^3, (−w^3/6)^−2, (1/2r^6)^-6, (4s^5t^−7/−2s^−2t^4)^3, and (3x^3y^0x*−2)^4⋅(y^2x^−4^5xy^−8)^3.
ziro4ka [17]

Use:\\\\(ab)^n=a^nb^n\\\\\left(\dfrac{a}{b}\right)^n=\dfrac{a^n}{b^n}\\\\(a^n)^m=a^{nm}\\\\\dfrac{a^n}{a^m}=a^{n-m}\\\\a^n\cdot a^m=a^{n+m}\\\\a^{-n}=\dfrac{1}{a^n}\\--------------------------------  

(-5p^3)^3=(-5)^3(p^3)^3=-125p^{(3)(3)}=-125p^9\\\\\left(-\dfrac{w^3}{6}\right)^{-2}\right)=\left(-\dfrac{6}{w^3}\right)^2=\left(\dfrac{6}{w^3}\right)^2=\dfrac{6^2}{(w^3)^2}=\dfrac{36}{w^{(3)(2)}}=\dfrac{36}{w^6}\\\\\left(\dfrac{1}{2r^6}\right)^{-6}=(2r^6)^6=2^6(r^6)^6=64r^{(6)(6)}=64r^{36}\\\\\left(\dfrac{4s^5t^{-7}}{-2s^{-2}t^4}\right)^3=\left(-\dfrac{4}{2}s^{5-(-2)}t^{-7-4}\right)^3=\left(-2s^7t^{-11}\right)^3\\\\=(-2)^3(s^7)^3(t^{-11})^3=-8s^{21}t^{-33}

(3x^3y^0x^{-2})^4(y^2x^{-4^5}xy^{-8})^3=(3x^{3+(-2)}1)^4(y^{2+(-8)}x^{-1024+1})^3.

=(3x^1)^4(y^{-6}x^{-1023})^3=3^4x^4(y^{-6})^3(x^{-1023})^3=81x^4y^{-18}x^{-3069}\\\\=81x^{4+(-3069)}y^{-18}=81x^{-3065}y^{-18}

7 0
3 years ago
How do I do this? Our teacher did not tell us how to work this problem
DochEvi [55]
Try making a different chart on a separate paper. Fill in the numbers to what they belong to and go through the questions carefully. Im sorry if this didn't help.
3 0
3 years ago
Read 2 more answers
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