9514 1404 393
Answer:
117°
Step-by-step explanation:
We assume you want to report your bearing as an angle measured CW from North. For conventional angles greater than 90°, it will be ...
450° -angle = 450° -333° = 117°
The bearing of the ship is 117°.
Answer:
x^(5/6) + 4(x^(7/3))
Step-by-step explanation:
Simplify x to the 1/3 power MULTIPLIED BY (x to the 1/2 power + 2x to the 2 power )
Simplify x^(1/3) × (x^(1/2) + (2x)^2)
= x^(1/3)(x^(1/2)) + x^(1/3)((2x)^2)
= x^(1/3+1/2) + 4(x^(1/3+2))
= x^(5/6) + 4(x^(7/3))
x^(1/3) is y such that y^3 = x
(x^(1/3) × x^(1/3) × x^(1/3)) = x^(1/3+1/3+1/3) = x^1 = x
x^(1/2) = √2 = y such that y^2 = x
(2x)^2 = 4x^2
Answer:
Solution given:
<ABC and <QRS are supplementary angles.
<ABC = 91°
we have
<ABC +<QRS=180°[supplementary]
<QRS=180°-91°=89°
m<QRS=89°
4 will multiply inside that brackets so
4(x-4)=4x-4
Answer:
<h2> 934boxes</h2><h2> 4 trips</h2>
Step-by-step explanation:
Given the total number of books 42,000
Ok, firstly let us calculate the number of boxes required, given that a box can contain 45 books
number of boxes= 42,000/45
number of boxes=933.3 boxes
approximately 934boxes
Also, given that the truck can carry online 250 boxes in one trip
then it must make 934/250= 3.7 trips
approximately the truck will make 4 trips to carry all the boxes
