For any polynomial equation, The Fundamental Theorem of Algebra tells you that the highest degree present will tell you how many complex roots the equation has. There are only two terms, "
" and "3". The
term has a degree of 5, its exponent. The 3 term has a degree of zero, because you could write it as
using the zero exponent rule.
The degrees present are 5 and 0. Choose the highest one, 5. So, the answer here is D.
Answer:
A
Step-by-step explanation:
Answer:
The first step is to divide all the terms by the coefficient of
which is 2.
The solutions to the quadratic equation
are:

Step-by-step explanation:
Considering the equation

The first step is to divide all the terms by the coefficient of
which is 2.
so


Lets now solve the equation by completeing the remaining steps
Write equation in the form: 
Solving for
,





Completing the square

Since, you had required to know the first step in completing the square for the equation above, I hope you have got the point, but let me quickly solve the remaining solution.
For
the solution are 
Solving


∵ Applying imaginary number rule 



Similarly, solving

∵ Applying imaginary number rule 

Therefore, the solutions to the quadratic equation are:

Answer:
or 3.61
Step-by-step explanation:
Draw a right triangle and use the Pythagorean Theorem to find the hypotenuse, using the given points to find the length of the two sides. See the attachment.