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3 years ago

11

Solve for 8y - 3 = 6y + 17 equation show work step by step

2 answers:

egoroff_w [7]3 years ago

8 0

8y - 3 = 6y + 17
+3 +3
____________
8y = 6y +20
-6y -6y
_______
2y = 20
-- --
2 2

y=10

vodomira [7]3 years ago

6 0

Jk,jg,k $8y-3=6y+17$
add 3 to both sides
$8y=6y+20$
subtract 6y from both sides
$2y=20$
and lastly divide both sides by 2
$y=10$

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Ilya [14]

Given:

The vertices of the rectangle ABCD are A(0,1), B(2,4), C(6,0), D(4,-3).

To find:

The area of the rectangle.

Solution:

Distance formula:

$D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Using the distance formula, we get

$AB=\sqrt{(2-0)^2+(4-1)^2}$

$AB=\sqrt{(2)^2+(3)^2}$

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Similarly,

$BC=\sqrt{(6-2)^2+(0-4)^2}$

$BC=\sqrt{(4)^2+(-4)^2}$

$BC=\sqrt{16+16}$

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$A=length \times width$

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3 years ago

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babymother [125]

Ay/x = cz

Multiply 'x' to both sides:

Ay = czx

Divide 'A' to both sides:

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3 years ago

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