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3 years ago

Find the measure of each acute angle. Thank you!

Mathematics

1 answer:

Wewaii [24]3 years ago

3 0

Answer:

55 for the top left and 35 for the top right

Step-by-step explanation:

The sum of the angles of a triangle is 180 degrees

7x+6 + 6x -7 + 90 = 180

Combine like terms

13x+89 = 90

Subtract 89 from each side

13x+89-89 = 180-89

13x = 91

Divide by 13

13x/13 = 91/13

x =7

The top left angle is

7x+6

7*7+6 = 49+6 = 55

The top right angle is

6x-7

6*7-7 = 42-7 = 35

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Answer:

The mid-point (p + q , q + p) of AB is the same distance from the x-axis and the y-axis

Step-by-step explanation:

* Lets explain how to solve the problem

- Any point will be equidistant from the x-axis and the y-axis must have

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- If (x , y) is the mid-point of a segment its endpoints are

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* Lets solve the problem

∵ Point A has coordinates (p , q)

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- The mid-point of AB is (x , y)

∵ $x=\frac{p+p+2q}{2}$

∴ $x=\frac{2p+2q}{2}$

- Take 2 as a common factor from the terms of the numerator

∴ $x=\frac{2(p+q)}{2}$

- Divide up and down by 2

∴ x = p + q

∵ $y=\frac{q+q+2p}{2}$

∴ $y=\frac{2q+2p}{2}$

- Take 2 as a common factor from the terms of the numerator

∴ $y=\frac{2(q+p)}{2}$

- Divide up and down by 2

∴ y = q + p

∴ The mid point of AB is (p + q , q + p)

- p + q is the same with q + p

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∵ p + q = q + p

∴ The coordinates of the mid-point of AB are equal

- According the explanation above

∴ The mid-point (p + q , q + p) of AB is the same distance from the

x-axis and the y-axis

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Answer:

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