To find instantaneous velocity given a position vs. time graph is find the derivative at that given point. In other words, find the slope at that point.
So at t = 1s, the velocity is 5/2 m/s.
Hope this helps!
Answer:
P₁ = 192 W and P₂ = 384 W
Explanation:
It is given that,
Resistor 1, ![R_1=12\ \Omega](https://tex.z-dn.net/?f=R_1%3D12%5C%20%5COmega)
Resistor 2, ![R_1=6\ \Omega](https://tex.z-dn.net/?f=R_1%3D6%5C%20%5COmega)
Voltage, V = 48 V
Power dissipated by resistor 1 is given by :
![P_1=\dfrac{V^2}{R_1}](https://tex.z-dn.net/?f=P_1%3D%5Cdfrac%7BV%5E2%7D%7BR_1%7D)
![P_1=\dfrac{(48)^2}{12}](https://tex.z-dn.net/?f=P_1%3D%5Cdfrac%7B%2848%29%5E2%7D%7B12%7D)
P₁ = 192 watts
Power dissipated by resistor 2 is given by :
![P_2=\dfrac{V^2}{R_1}](https://tex.z-dn.net/?f=P_2%3D%5Cdfrac%7BV%5E2%7D%7BR_1%7D)
![P_2=\dfrac{(48)^2}{6}](https://tex.z-dn.net/?f=P_2%3D%5Cdfrac%7B%2848%29%5E2%7D%7B6%7D)
P₂ = 384 watts
So, the power dissipated by both the resistors is 192 watts and 384 watts respectively. Hence, this is the required solution.
The correct answer is C. amplitude.
Have an awesome day!