Question

Ignoring air​ resistance, an object in free fall will fall d feet in t​ seconds, where d and t are related by the algebraic model d equals 16 t squared. ​(a) How long will it take the object to fall 1148 ​ft? ​(b) If the object is in free fall for 18.5 sec after it is​ dropped, how high was the object when it was​ dropped?

Answer 1

Explanation:

Given that,

An object in free fall will fall d feet in t​ seconds, where d and t are related by the algebraic model as :

$d=16t^2$..........(1)

(a) We need to find the time taken by the object to fall 1148 ft. Put this in equation (1) as :

$16t^2=1148$

$t=\sqrt{71.75}$

t = 8.47 seconds

(b) If the object is in free fall for 18.5 sec after it is​ dropped, then the height of the object is given by :

$d=16(18.5)^2$

d = 5476 ft

Hence, this is the required solution.