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kogti [31]
4 years ago
12

Ignoring air​ resistance, an object in free fall will fall d feet in t​ seconds, where d and t are related by the algebraic mode

l d equals 16 t squared. ​(a) How long will it take the object to fall 1148 ​ft? ​(b) If the object is in free fall for 18.5 sec after it is​ dropped, how high was the object when it was​ dropped?
Physics
1 answer:
Lostsunrise [7]4 years ago
7 0

Explanation:

Given that,

An object in free fall will fall d feet in t​ seconds, where d and t are related by the algebraic model as :

d=16t^2..........(1)

(a) We need to find the time taken by the object to fall 1148 ft. Put this in equation (1) as :

16t^2=1148

t=\sqrt{71.75}

t = 8.47 seconds

(b) If the object is in free fall for 18.5 sec after it is​ dropped, then the height of the object is given by :

d=16(18.5)^2

d = 5476 ft

Hence, this is the required solution.

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What net force would be required for a 50.5 kg wolf to accelerate at 5.0 m/s^2
Basile [38]

Answer:

\boxed {\boxed {\sf 252.5 \ Newtons }}

Explanation:

Force is the push or pull on object that can cause different things, like acceleration. According to Newton's 2nd Law of Motion, it is the product of mass and acceleration.

F=m*a

The mass of the wolf is 50.5 kilograms and the acceleration is 5.0 meters per square second. Therefore:

  • m= 50.5 \ kg
  • a= 5.0 \ m/s^2

Substitute the values into the formula.

F= 50.5 \ kg * 5.0 \ m/s^2

Multiply.

F=252.5 \ kg*m/s^2

  • 1 kilogram meter per square second is equal to 1 Newton.
  • Our answer of 252.5 kg*m/s² is equal to 252.5 Newtons.

F= 252.5 \ N

The force required is <u>252.5 Newtons</u>.

4 0
3 years ago
6. A total of 135 J of work is done on a gaseous refrigerant as it undergoes compression. If
Gwar [14]

Answer:

Eh = 21 [J]

Removed as heat.

Explanation:

This is a case of energy conservation, we have to take into account the energies that go in and out of the system. In this case, 135 [J] of energy are entered in the form of work of the compressor to the chamber where the refrigerant is compressed, now of these 135 [J] 114 [J] were used as internal energy, this internal energy is used to increase the pressure and temperature of the refrigerant.

In this way the rest of the energy of the 135 [J] was lost in the form of heat to determine this loss of energy, we simply perform the arithmetic subtraction.

Eh = 135 - 114 = 21 [J]

Eh = 21 [J]

6 0
3 years ago
PLEASE HELPPP!!! D:
pogonyaev

Answer:

a is 4.6 x 10-2m

b is 1x8204m

Explanation:

The fire net is actually going past zero into a negative vertical displacement. Essentially because again, we're saying that why initial equals thirty eight meters. The person is falling down to zero meters. Zero meters is where the fire that is. And then after the person stretches the fire. Yet it has a certain vertical displacement. But this particles placement is negative. So here we're going to choose the negative value. so trying to see how much of the fire net would stretch if the person was lying on tough it and if the person jumped from a height of thirty eight meters. So for here Mass is going to be equal to sixty two kilograms and why initial for party is going to be twenty meters and then why final is going to be negative one point four meters And so in order to find in order to find this is an instance, essentially, this is an instance perspective in the sense that we need this data in order to figure out this during constant so we can see that energy initial equals energy final and then we consider it mg y initial equals mg.

7 0
4 years ago
Acceleration is the rate at which what happens?
belka [17]

Answer:

Acceleration is a vector quantity that is defined as the rate at which an object changes its velocity. An object is accelerating if it is changing its velocity.

may be it helped you

6 0
3 years ago
4. A car accelerates at 2.5 m/s^2, covers 4 km in 0.8 min. How fast was it moving at the beginning
alukav5142 [94]

Answer:

Initial velocity, u = 23.33 m/s

Explanation:

Given the following data;

Acceleration = 2.5 m/s²

Distance = 4 km to meters = 4000 meters

Time = 0.8 mins to seconds = 0.8 * 60 = 48 seconds.

To find the initial velocity, we would use the second equation of motion;

S = ut + \frac {1}{2}at^{2}

Where;

S represents the displacement or height measured in meters.

u represents the initial velocity measured in meters per seconds.

t represents the time measured in seconds.

a represents acceleration measured in meters per seconds square.

Substituting into the equation, we have;

4000 = u*48 + ½*2.5*48²

4000 = 48u + 1.25*2304

4000 = 48u + 2880

48u = 4000 - 2880

48u = 1120

Initial velocity, u = 1120/48

Initial velocity, u = 23.33 m/s

8 0
3 years ago
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