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3 years ago

15

Which type of cells in your eyes allows you to see the color violet?

1 answer:

BaLLatris [955]3 years ago

3 0

The cones present on the retina are the cells that help you see the colors.....there are mainly three types....red blue and green, cones but they mix to generate different colours !

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Find the power load P in kilowatts of an electrical circuit that takes a current I of 17 amperes at a voltage V of 320 volts if

MA_775_DIABLO [31]

Answer: P = 5.44 KW

Explanation:

The formula for calculating power is expressed as

P = VI

where

v is the voltage

I is the current

From the information given,

v = 320

I = 17

Thus,

P = 320 x 17 = 5440 W

We would convert it to KW by dividing by 1000. It becomes

P = 5440/1000

P = 5.44 KW

6 0

1 year ago

A sound system is being set up in a gazebo in a park. It needs to produce music so that everyone can hear it. How much power wou

Agata [3.3K]

Answer:

Power of the speakers = 1.57 $\times 10^{-6} W$

Explanation:

There are speakers setup in a park and we have to find the power it would require to have intensity of sound to be $10^{-8} W/m^2$ at a distance of 5 meter.

In one dimension the intensity is constant as the wave travels. In two or three dimensions, however, the intensity decreases as you get further from the source.

Intensity is inversely proportional to the square of the distance from the point of sound production.

Here area = 2 $\times \pi \times r^{2}$

area = 157 $m^{2}$

$Intensity = \frac{Power}{Area}$

$Power = intensity \times area$

Power = $10^{-8} \times 157Power = 1.57 [tex]\times 10^{-6} W$

7 0

3 years ago

A 91.1 kg horizontal circular platform rotates freely with no friction about its center at an initial angular velocity of 1.73 r

KIM [24]

Answer:

$\omega_f = 1.08 rad/s$

Explanation:

As we know that there is no external torque on the system of platform, banana and the monkey

so the angular momentum of the system will remains conserved

so here we can say

$L_i = L_f$

$I_o\omega = (I_o + m_1r_1^2 + m_2r_2^2)\omega_f$

here we know that

$I_o = \frac{1}{2}mR^2$

$I_o = \frac{1}{2}(91.1)(1.61)^2 = 118.1 kg m^2$

$m_1 = 9.41 kg$

$r_1 = \frac{4}{5}(1.61) = 1.29 m$

$m_2 = 21.1 kg$

Now from above equation

$118.1(1.73) = (118.1 + 9.41(1.29^2) + 21.1(1.61^2))\omega_f$

$118.1(1.73) = 188.45\omega_f$

$\omega_f = 1.08 rad/s$

8 0

3 years ago

Two balls of equal mass collide and stick together as shown in the figure. The initial velocity of ball B is twice that of ball

Mice21 [21]

The angle above the horizontal of the motion of mass A + B after the collision. as well as others are mathematically given as

$\theta f = 26.3 \deg$
vf/vA= 0.94
2vf^2 / 5vA^2 = 0.35

<h3>What is Collison equilibrium?</h3>

According to the collision hypothesis of chemistry, chemical reactions happen when two molecules or atoms collide.

Generally, the equation for Collison equilibrium is mathematically given as

For horizontal motion

mvAx+m2vAx = 2mvfx

For vertical motion

-mvAy+m2vAy = 2mvfy

vfy = 1/2 vAy

$\tan \theta f = vfy/vfx \\\\\tan \theta f = 1/3 vAy/vAx \\\\\tan \theta f = vAy/vAx \\\\\theta f = tan-1 ( 1/3 tan (56) )\\\\$

$\theta f = 26.3 \deg$

(b)

$v fy = vf sin \theta f\\\\vAy = vA sin theta i\\\\vf/vA = vfy/vAy sin( \theta i)/sin(\theta f)\\\\vf/vA = 1/2 sin(56)/sin(26.3) \\\\$

vf/vA= 0.94

(c)

$Ef/Ei = \frac{(1/2 * (2m) * (vf)^2) }{ (1/2 * m * (vA)^2) + 1/2*m*(2vA)^2) ]}$

2vf^2 / 5vA^2 = 0.35

In conclusion, The angle above the horizontal of the motion of mass A + B after the collision. as well as others

$\theta f = 26.3 \deg$

vf/vA= 0.94

2vf^2 / 5vA^2 = 0.35

Read more about collision theory

brainly.com/question/20628781

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8 0

2 years ago

Someone who has nostres that are not separated equally has which sensory issue?

Zina [86]

Answer:

i think B. Deviated septum

5 0

3 years ago