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IgorLugansk [536]
3 years ago
13

WHO WANTS 60 POINTS??!!!! HELP ME!!!!

Mathematics
2 answers:
STALIN [3.7K]3 years ago
7 0
The correct answer to question 1 is: (C. P (v)=4500v
The correct answer to question 2 is: (A. 12

Hope i helped!:)
Komok [63]3 years ago
6 0
Okay the only one that I have learned so far, is the second question.  Just plug in the answer choices as x, and see which ones match up to 2. Hope this helps.

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Please anwser im having the hardest time on this picture
Free_Kalibri [48]
What you do first is add the books 42 + 85 + 69 which equals 196. Then divide 196 by 7 and you get 28 :)
3 0
4 years ago
Read 2 more answers
Find the sum of 4x^3+2x^2-4x+3 and 7x^3-4x^2+7x+8
Alchen [17]

The sum means addition.

Add  the like terms together.

4x^3+2x^2-4x+3

+ 7x^3-4x^2+7x+8

4x^3 + 7x^3 = 11x^3

2x^2 + -4x^2 = -2x^2

-4x +7x = 3x

3 +8 = 11

The answer is : 11x^3 - 2x^2 + 3x + 11

4 0
3 years ago
Read 2 more answers
-3x + 7y = -1<br> - 2x + 5y=0
Talja [164]
(X,Y) = (9/13 , 2/13)
6 0
3 years ago
Rapid Rental Car charges a $40 rental fee, $15 for gas, and $0.25 per mile driven. For the same car, Capital Cars charges $45 fo
pochemuha

Answer: y = 40 + 15 + .25x , y = 45 + .35x


Step-by-step explanation: What is your question? if your looking to put them into forms then here it is


6 0
3 years ago
2. Determine the sum of the first 400 ODD numbers.<br><br>​
il63 [147K]

Odd numbers take the form 2n-1, where n\ge1 is an integer. When n=400, the last odd number would be 799. So we're adding

S=1+3+5+\cdots+795+797+799

By reversing the order of terms, we have

S=799+797+795+\cdots+5+3+1

and we can pair up terms in both sums at the same position to write

2S=(1+799)+(3+797)+(5+795)+\cdots(795+5)+(797+3)+(799+1)

so that we are basically adding 400 copies of 800, and from there we can find the value of the sum right away:

2S=400\cdot800\implies S=160,000

###

We could also make use of the formulas,

\displaystyle\sum_{i=1}^n1=n

\displaystyle\sum_{i=1}^ni=\dfrac{n(n+1)}2

We have

S=\displaystyle\sum_{i=1}^{400}(2i-1)=2\sum_{i=1}^{400}i-\sum_{i=1}^{400}1=400(400+1)-400=400^2=160,000

3 0
4 years ago
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