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Murljashka [212]

3 years ago

14

Paulie is buying a shirt that was originally priced at $15. The store has a today-only discount of 25%. What is today’s price fo

r the shirt?

1 answer:

fenix001 [56]3 years ago

3 0

Answer:

he is buying it for 11.25. you get this buy multiplying 15 by 25% which equals 3.75 then you subtract 15 by 3.75 and you get 11.25

hope it helps

please mark as brainliest

Step-by-step explanation:

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A movie theatre has 26 rows of seats.There are 18 seats in each row.How many seats are there in all?

lawyer [7]

468 seats is the answer.

26 x 18

or

13 x 2 x 9 x 2

both equal 468

5 0

3 years ago

Scientific notation<br> 9.78 × 10^5 - 732,000<br> It has to be either 2.46 × 10^5 or 2.46 × 10^3

Morgarella [4.7K]

Answer:

$2.46\times 10^5$

Step-by-step explanation:

$9.78 \times 10^5 - 732,000\\= 9.78 \times 10^5 - 7.32 000\times 10^5\\= 9.78 \times 10^5 - 7.32\times 10^5\\= 2.46\times 10^5$

3 0

4 years ago

Jimmy loaded three bags of sand into his wheelbarrow. The bags weighed 24

Rudik [331]

The whole numbers add up to 100. So now we are left with 1/2 or 0.5, 3/5 or .60, and 1/8 or .125. Those add up to 1.225 so the amount of sand in pounds in the wheelbarrow is 101.225. Hope I helped! If you have any questions just leave a comment.

3 0

3 years ago

Slove for g<br> 3/16= -5/4 +g

PSYCHO15rus [73]

Answer:

+g=3/16+5/4

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8 0

2 years ago

A spinner has 10 equally sized sections, 5 of which are gray and 5 of which are blue. The spinner is spun twice. What is the pro

zhenek [66]

Answer:

$P(Gray\ and\ Blue) = \frac{1}{4}$

Step-by-step explanation:

Given

$Sections = 10$

$n(Gray) = 5$

$n(Blue) = 5$

Required

Determine P(Gray and Blue)

Using probability formula;

$P(Gray\ and\ Blue) = P(Gray) * P(Blue)$

Calculating P(Gray)

$P(Gray) = \frac{n(Gray)}{Sections}$

$P(Gray) = \frac{5}{10}$

$P(Gray) = \frac{1}{2}$

Calculating P(Gray)

$P(Blue) = \frac{n(Blue)}{Sections}$

$P(Blue) = \frac{5}{10}$

$P(Blue) = \frac{1}{2}$

Substitute these values on the given formula

$P(Gray\ and\ Blue) = P(Gray) * P(Blue)$

$P(Gray\ and\ Blue) = \frac{1}{2} * \frac{1}{2}$

$P(Gray\ and\ Blue) = \frac{1}{4}$

3 0

3 years ago