Answer:
b
Explanation:
The correct answer would be 6.4 x 
cells/ul.
For 1 x 10-6 dilution, the plating factor is . To find the number of bacteria in the original sample, the plating factor is multiplied by the colony count per ul.
<em>Number of viable bacteria = plating factor x colony count/ul</em>
Since 10 ul gives 64 colonies. 1 ul will give:
64/10 = 6.4 colonies.
Therefore, the viable bacteria in the original sample = 6.4 x cells/ul
The correct option is b.
They are similar to plants because they are they’re just the exact same as plants
The answer is D. The surface area of rocks decreases because of acid rain
Hope this helps you<3
Answer:
A. Overtillage can increase the rate of humus decomposition
Explanation:
We refer to humus as any material of an organic nature that undergoes soil degradation. Humus is very important for agriculture because it has high nutrient levels that it provides to all crops. This causes more crop productivity, increases the producer's profit and increases the number of food available to the population.
Humus is a difficult to decompose material, but under favorable conditions it can decompose quite easily. Due to the presence of large amount of burnt organic matter in the soil, it is sometimes difficult to increase the humus content, so the exhaustion of this organic matter is caused by over tillage, especially in regions of tropical and sub-tropical climate, poorly managed. farmer protection and unprotected effects of erosion.
Answer:
1/4
Explanation:
Given that the F2 cross produces offspring according to the expected 9:3:3:1 ratio.
YyRr X YyRr:
Let us break the dihybrid cross into individual monohybrid crosses.
Yy X Yy :
Y y
Y YY Yy
y Yy yy
2/4 or 1/2 of the offspring are heterozygous for the trait.
Similarly, in Rr X Rr cross, 1/2 of the offspring are heterozygous for the trait.
Together, 1/2 * 1/2 = 1/4 of F2 plants are expected to be heterozygous for both traits.
