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Answer:
D. The oxygen side is partially negative because electrons are pulled toward the oxygen side.
Explanation:
The water molecule is polar by the virtue of covalent bonds and the hydrogen bonds within and between its molecule.
The oxygen side is partially negative because the electrons are pulled toward the oxygen side.
Between oxygen and hydrogen that makes up the water molecule, oxygen is more electronegative.
An electronegative atom has more affinity for electrons. Since the electrons in the molecule of water is shared between hydrogen and oxygen, the more electronegative specie which is water draws the electron more to itself.
This leaves a net negative charge on the oxygen atom.
Answer:
u need to make sure that comparison is = to shapes and then find the shapes sizes and add them
Answer: <u><em>C. Steel</em></u>
Explanation: <em><u>When a sound wave travels through a solid body consisting</u></em>
<em><u /></em>
<em><u>of an elastic material, the velocity of the wave is relatively</u></em>
<em><u /></em>
<em><u>high. For instance, the velocity of a sound wave traveling</u></em>
<em><u /></em>
<em><u>through steel (which is almost perfectly elastic) is about</u></em>
<em><u /></em>
<em><u>5,060 meters per second. On the other hand, the velocity</u></em>
<em><u /></em>
<em><u>of a sound wave traveling through an inelastic solid is</u></em>
<em><u /></em>
<em><u>relatively low. So, for example, the velocity of a sound wave</u></em>
<em><u /></em>
<em><u>traveling through lead (which is inelastic) is approximately</u></em>
<em><u /></em>
<em><u>1,402 meters per second.</u></em>
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The speed of the combined carts after the collision is 0.25 m/s
Explanation:
We can solve this problem by using the principle of conservation of momentum. In fact, the total momentum of the system must be conserved before and after the collision, so we can write:
where:
is the mass of the first cart
is the initial velocity of the first cart
is the mass of the second cart
is the initial velocity of the second cart
is the final combined velocity of the two carts
Re-arranging the equation and substituting the values, we find: the final velocity:

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