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Humidity is 90 it will be hotter so the child has to add water to the goldfish bowl
Power = Work/time
Work= energy
Potential energy =mxgxh
Power=mxgxh/t
Power=68x10x7/9
Power=529 watts
Answer:
As the object moves parallel to principle axis the image of the object will continuously moves away from the principal axis so the horizontal distance will increase
Explanation:
As the object is moving towards the lens then in that case first the image will form between the focus and double the distance of focus.
So here the image is diminished
now when the object is at large distance from from lens then its image will form at focus and it is of very small size
Now as the object comes closer to the lens till the object distance is 2F the image size will increase but smaller then object size
Now when object is between F and 2F then the image size will be more than object size and it will increase to infinite magnification
So overall we can say that as the object moves parallel to principle axis the image of the object will continuously moves away from the principal axis so the horizontal distance will increase
Answer:
<em> The intensity would be 0.01432 W/</em>
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Explanation:
The sound intensity is the power that is transmitted by a sound wave per unit area.
Given that
Power output P of the 75-piece orchestra = 72.0 W
The listener's distance r = 20.0 m
The intensity of sound waves (I) can be obtained with the expression below;
I = P/A .............. 1
where P is the power
A is the area, in this case, at the distance r the sound is radiated through a sphere.
A = area of a sphere = 4π
putting it into equation 1, the intensity would be;
I = P/ 4π
Substituting our values we have;
I = 72.0 W / 4 π 
I = 0.01432 W/
Therefore the intensity would be 0.01432 W/
