Answer:
The mass of the ball is 0.23 kg
Explanation:
Given that
radius ,r= 3.74 cm
Density of the milk ,ρ = 1.04 g/cm³ = 1.04 x 10⁻³ kg/cm³
Normal force ,N= 9.03 x 10⁻² N
The volume of the ball V
![V=\dfrac{4}{3}\pi r^3](https://tex.z-dn.net/?f=V%3D%5Cdfrac%7B4%7D%7B3%7D%5Cpi%20r%5E3)
![V=\dfrac{4}{3}\times \pi \times 3.74^3\ cm^3](https://tex.z-dn.net/?f=V%3D%5Cdfrac%7B4%7D%7B3%7D%5Ctimes%20%5Cpi%20%5Ctimes%203.74%5E3%5C%20cm%5E3)
V= 219.13 cm³
The bouncy force on the ball = Fb
Fb = ρ V g
Fb + N = m g
m=Mass of the ball = Density x volume
m = γ V , γ =Density of the Ball
ρ V g + N = γ V g ( take g= 10 m/s²)
![\gamma =\dfrac{N+\rho V g}{V g}](https://tex.z-dn.net/?f=%5Cgamma%20%3D%5Cdfrac%7BN%2B%5Crho%20V%20g%7D%7BV%20g%7D)
![\gamma =\dfrac{9.03\times 10^{-2}+1.04\times 10^{-3}\times 219.13\times 10}{219.13\times 10}](https://tex.z-dn.net/?f=%5Cgamma%20%3D%5Cdfrac%7B9.03%5Ctimes%2010%5E%7B-2%7D%2B1.04%5Ctimes%2010%5E%7B-3%7D%5Ctimes%20219.13%5Ctimes%20%2010%7D%7B219.13%5Ctimes%2010%7D)
γ = 0.00108 kg/cm³
m = γ V
m = 0.00108 x 219.13
m= 0.23 kg
The mass of the ball is 0.23 kg
same, stapler, gravity, motion, acceleration
Answer: final Velocity v = 10.2m/s
Explanation:
Final speed v(t) is given as
v(t) = u + at .......1
Where; u = the initial speed
a = acceleration
t = time taken
The total distance travelled d is given as
d = ut + 1/2(at^2)
Given
d = 5.0m
u = 2.0m
a = g = 10m/s2 (acceleration due to gravity)
Substituting into the equation above we have
5 = 2t + 5t^2
5t^2 +2t -5 = 0
Applying the quadratic formula. We have;
t = 0.82s & t = -1.22s
t cannot be negative
t = 0.82s
From equation 1 above
v = 2.0m/s + 10(0.82)m/s
v = 10.2m/s