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expeople1 [14]
2 years ago
12

In many cartoon shows, a character runs of a cliff, realizes his predicament and lets out a scream. He continues to scream as he

falls. If the physical situation is portrayed correctly, from the vantage point of an observer at the foot of the cliff, the pitch of the scream should be Group of answer choices
Physics
1 answer:
Rzqust [24]2 years ago
5 0

Answer:

Increasing until terminal velocity is reached

Explanation:

Provided the scream is a constant pitch at the source, Doppler effect will make the pitch increase as the velocity of the source towards the listener increases.

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As a rubber band and moves forward, which of the following is true
Yuki888 [10]

Answer:

It can go back to it's original shape

Explanation:

7 0
3 years ago
WA
brilliants [131]

Answer:

the answers the correct one is d

Explanation:

The speed of sound is constant so we can use the relations of uniform motion

           v = x / t

            x = v t

now let's calculate the distance for each person

t = 5s

         x₁ = 300 5

         x₁ = 1500 m

t = 6s

         x₂ = 300 6

         x₂ = 1800 m

therefore we have two possibilities

a) the two people are on the same side, therefore the distance between them is

         Δx = x₂- x₁

         Δx = 1800 - 1500

         Δx = 300 m

       

let's reduce to km

         Δx = 0.300 km

b) people are on opposite sides of the sound

         Δx = x₂ + x₁

         Δx = 1800 + 1500

         Δx = 3300 m

         Δx = 3.3 km

when checking the answers the correct one is d

3 0
2 years ago
Express newton pascal joule and watt in fundamental unit​
Nadya [2.5K]

i added an image. i hope it helped :)

3 0
3 years ago
What is the change in potential energy of an energetic 72 kg hiker who makes it from the floor of death valley to the top of mt.
storchak [24]
<span>The lowest point in Death Valley is 85 m below sea level. The summit of nearby Mt. Whitney has an elevation of 4420 m. </span>
3 0
3 years ago
¿cual es la velocidad de un haz de electrones que marchan sin desviarse cuando pasan a traves de un campo magnetico perpendicula
Elina [12.6K]

Answer:

La velocidad del haz de electrones es 1.78x10⁵ m/s. Este valor se obtuvo asumiendo que el campo magnético dado (3500007) estaba en tesla y que la fuerza venía dada en nN.

Explanation:

Podemos encontrar la velocidad del haz de electrones usando la Ley de Lorentz:

F = |q|vBsin(\theta)     (1)

En donde:

F: es la fuerza magnética = 100 nN

q: es el módulo de la carga del electron = 1.6x10⁻¹⁹ C

v: es la velocidad del haz de electrones =?

B: es el campo magnético = 3500007 T

θ: es el ángulo entre el vector velocidad y el campo magnético = 90°

Introduciendo los valores en la ecuación (1) y resolviendo para "v" tenemos:

v = \frac{F}{qBsin(\theta)} = \frac{100 \cdot 10^{-9} N}{1.6 \cdot 10^{-19} C*3500007 T*sin(90)} = 1.78 \cdot 10^{5} m/s            

Este valor se calculó asumiendo que el campo magnético está dado en tesla (no tiene unidades en el enunciado). De igual manera se asumió que la fuerza indicada viene dada en nN.

Entonces, la velocidad del haz de electrones es 1.78x10⁵ m/s.  

Espero que te sea de utilidad!                                        

7 0
3 years ago
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