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Serjik [45]
3 years ago
11

Need help, Iĺl give brainliest <3

Mathematics
2 answers:
Pavel [41]3 years ago
8 0

Step-by-step explanation:

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iren [92.7K]3 years ago
5 0
What is the question tho ?
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Oliga [24]

Answer:

Part A)

The height of the water level in the rectangular vessel is 2 centimeters.

Part B)

4000 cubic centimeters or 4 liters of water.

Step-by-step explanation:

We are given a cubical vessel that has side lengths of 10cm. The vessel is completely filled with water.

Therefore, the total volume of water in the cubical vessel is:

V_{C}=(10)^3=1000\text{ cm}^3

This volume is poured into a rectangular vessel that has a length of 25cm, breadth of 20cm, and a height of 10cm.

Therefore, if the water level is h centimeters, then the volume of the rectangular vessel is:

V_R=h(25)(20)=500h\text{ cm}^3

Since the cubical vessel has 1000 cubic centimeters of water, this means that when we pour the water from the cubical vessel into the rectangular vessel, the volume of the rectangular vessel will also be 1000 cubic centimeters. Hence:

500h=1000

Therefore:

h=2

So, the height of the water level in the rectangular vessel is 2 centimeters.

To find how how much more water is needed to completely fill the rectangular vessel, we can find the maximum volume of the rectangular vessel and then subtract the volume already in there (1000 cubic centimeters) from the maximum volume.

The maximum value of the rectangular vessel is given by :

A_{R_M}=20(25)(10)=5000 \text{ cm}^3

Since we already have 1000 cubic centimeters of water in the vessel, this means that in order to fill the rectangular vessel, we will need an additional:

(5000-1000)\text{ cm}^3=4000\text{ cm}^3

Sincer 1000 cubic centimeters is 1 liter, this means that we will need four more liters of water in order to fill the rectangular vessel.

3 0
3 years ago
Read 2 more answers
Find the value of x in the figure
Sedaia [141]
If there is a picture i could tell you 

4 0
3 years ago
Read 2 more answers
Engineers must consider the diameters of heads when designing helmets. The company researchers have determined that the populati
IrinaK [193]

Answer:

1. The minimum head breadth that will fit the clientele is of 3.95-in.

2. The maximum head breadth that will fit the clientele is of 9.25-in.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean of 6.6-in and a standard deviation of 1.1-in.

This means that \mu = 6.6, \sigma = 1.1

1. What is the minimum head breadth that will fit the clientele?

The 0.8th percentile, which is X when Z has a p-value of 0.008, so X when Z = -2.41.

Z = \frac{X - \mu}{\sigma}

-2.41 = \frac{X - 6.6}{1.1}

X - 6.6 = -2.41*1.1

X = 3.95

The minimum head breadth that will fit the clientele is of 3.95-in.

2. What is the maximum head breadth that will fit the clientele?

The 100 - 0.8 = 99.2nd percentile, which is X when Z has a p-value of 0.992, so X when Z = 2.41.

Z = \frac{X - \mu}{\sigma}

2.41 = \frac{X - 6.6}{1.1}

X - 6.6 = 2.41*1.1

X = 9.25

The maximum head breadth that will fit the clientele is of 9.25-in.

8 0
2 years ago
HELPPPPP PLSSSSSSS pls
Vilka [71]

Sorry, not sure how to describe it, but the lower the temperature, the higher the hot chocolate sales.

3 0
2 years ago
Two factory plants are making TV panels. Yesterday, Plant A produced 16,000 panels. Five percent of the panels from Plant A and
weeeeeb [17]

Answer:

Number of panels produced by Plant B is 8,000.

Step-by-step explanation:

The number of panels produced by Plant A  = 16,000

The number of defective panels from A = 5%

Now, 5% of 16,000 = \frac{5}{100}  \times 16,000 = 800

So, out of  16,000 panels produced by pant A , 800 are defective. .. (1)

Let us assume number of panels produced by Plant B  = m

The number of defective panels from B = 2%

Now, 2% of m = \frac{2}{100}  \times m = 0.02 m

So, out of total m panels produced by pant B , 0.02 m are defective. .. (2)

Now, total panels produced over all = Panels by A  + Panels by B

= 16,000 + m

The percentage of defected panels over all = 4%

Now, 4% of (16,000 + m) = \frac{4}{100}  \times (16,000+m)  = (0.04)(16,000 + m)

Also, the total number of defective panels = Defective from A  + Defective from B

⇒(0.04)(16,000 + m)  =  800 +   0.02 m   from (1) and (2)

or, 640 + 0.04 m = 800 + 0.02

or, 0.02 m = 160

⇒ m = 160 /0.02 = 8,000

or, m = 8,000

Hence, Number of panels produced by Plant B is 8,000.

5 0
3 years ago
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