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3 years ago

Need help, Iĺl give brainliest <3

Mathematics

2 answers:

Pavel [41]3 years ago

8 0

Step-by-step explanation:

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iren [92.7K]3 years ago

5 0

What is the question tho ?

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The length of the shadow of an office building is 35 feet. At the same time of the day, Donovan Mitchell, who is 6.1 feet tall,

Vadim26 [7]

Answer:

175

Step-by-step explanation:

35 times 5 is 175

Hope This Helped

4 0

1 year ago

A consumer organization estimates that 35% of the households in a particular community have one television set, 39% have two set

nikitadnepr [17]

Answer:

90%

Step-by-step explanation:

Probability of households with one TV = 35% or 0.35

Probability of households with two sets = 39% or 0.39

Probability of households with three or more = 16% or 0.16

The probability of a household with no TV set = 0.10 or 10% (1 - 0.35 - 0.39 - 0.16)

Therefore, the probability of a household with at least one or more sets = 90% (35% + 39% + 16%) or 100% - 10%.

Probability is the chance that something may occur out of many events. To calculate probability, we divide the number of events by the number of possible outcomes.

5 0

2 years ago

Can someone help me with these 4 questions please :) .

butalik [34]

60² + 30² = 4500²

Opposite corner = 67.08 ft.

6² + 8² = 100²

The wire must be 10 ft.

7² + 14² = 245²

The rope is 15.65 ft.

180² + 300² = 122400²

He ran 349.85 ft.

I'm not too sure about question 3.

8 0

2 years ago

In analyzing the city and highway fuel efficiencies of many cars and trucks, the mean difference in fuel efficiencies for the 60

Olegator [25]

Answer:

$7.38-1.96\frac{2.51}{\sqrt{601}}=7.18$

$7.38+1.96\frac{2.51}{\sqrt{601}}=7.58$

For this case the confidence interval is given by :

$7.18 \leq \mu \leq 7.58$

Step-by-step explanation:

Data provided

$\bar X=7.38$ represent the sample mean for the fuel efficiencies

$\mu$ population mean

s=2.51 represent the sample standard deviation

n=601 represent the sample size

Confidence interval

The formula for the confidence interval of the true mean is given by:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

The degrees of freedom for this case is given by:

$df=n-1=601-1=600$

The Confidence level for this case is 0.95 or 95%, and the significance level $\alpha=0.05$ and $\alpha/2 =0.025$ and the critical value is given by $t_{\alpha/2}=1.96$