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gladu [14]
2 years ago
11

If cotθ=1/

lign="absmiddle" class="latex-formula"> , the value of sec^{2} θ + cosec^{2} θ is
a) 1
b) 40/9
c) 38/9
d) 5\frac{1}{3}
Mathematics
1 answer:
kobusy [5.1K]2 years ago
7 0

\text{Given  that,}~\\\\\cot \theta = \dfrac 1{\sqrt 3} \\\\\\\text{So,}~~ \tan \theta = \dfrac 1{\cot \theta} = \sqrt 3\\\\\\\sec^2 \theta + \csc^2 \theta   \\\\=(1+\tan^2 \theta) + (1 + \cot^2 \theta)\\\\=1 +\left (\sqrt 3 \right)^2 + 1 + \left(\dfrac 1{\sqrt 3} \right)^2\\\\=1 +3 + 1 + \dfrac 13 \\\\= 5  + \dfrac 13 \\\\= 5 \dfrac 13

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What's the answer
SVEN [57.7K]

a) We kindly invite to check the image attached below to see a detailed graph of the <em>piecewise</em> function.

b) The <em>piecewise</em> function is continuous.

<h3>How to understand a piecewise function</h3>

A <em>piecewise</em> function is a <em>conditional</em> combination of two or more functions, whose expression depends on which value of the domain is the function evaluated at.

a) The <em>piecewise</em> function described in the question is plotted on a graphing tool (i.e. <em>Desmos</em>), whose result is presented in the image attached below.

b) A function is <em>continuous</em> if and only if there is one value from range for every value of domain. The <em>piecewise</em> function is continuous as <em>linear</em> functions are continuous and the two functions of the <em>conditional</em> combination have the same value for x = 30.

To learn more on piecewise functions: brainly.com/question/12561612

#SPJ1

7 0
2 years ago
One Sunday, 120 days before Christmas, Aldsworth store publishes an advertisement saying ‘120 shopping days until Christmas'. Al
Lena [83]

Answer:

(a)18

(b)1089

(c)Sunday

Step-by-step explanation:

The problem presented is an arithmetic sequence where:

  • First Sunday, a=1
  • Common Difference (Every subsequent Sunday), d=7

We want to determine the number of Sundays in the 120 days before Christmas.

(a)In an arithmetic sequence:

\text{The nth term}, T_n=a+(n-1)d\\T_n \leq 120\\$Therefore:$\\1+7(n-1) \leq 120\\1+7n-7\leq 120\\7n-6\leq 120\\7n\leq 120+6\\7n\leq 126\\$Divide both sides by 7$\\n\leq 18

Since the result is a whole number, there are 18 Sundays in which Aldsworth advertises.

Therefore, Aldsworth advertised 18 times.

(b)Next, we want to determine the sum of the first 18 terms of the sequence

1,8,15,...

\text{Sum of a sequence}, S_n=\frac{n}{2}( 2a+(n-1)d)\\S_{18}=\frac{18}{2}( 2*1+(18-1)*7)\\=9(2+17*7)\\=9(2+119)\\=9*121\\S_{18}=1089

The sum of the numbers of days published in all the advertisements is 1089.

(c)SInce the 120th day is the 18th Sunday, Christmas is on Sunday.

6 0
3 years ago
I need help pls someone:(
Svetlanka [38]

Answer:

7/30

Step-by-step explanation:

3 0
2 years ago
What are the factors of y^2+12y+35=0?
Evgen [1.6K]
The factors is 5,4,3,6,12
5 0
3 years ago
Which of the following graphs could describe the system of equations?
Pepsi [2]

Answer:

The answer is...

Step-by-step explanation:

Purplea

4 0
2 years ago
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