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vesna_86 [32]
3 years ago
8

The mad hatter buys his tea in a bulk from the local store .A case of tea bags cost 15 gold cons

Mathematics
1 answer:
Firdavs [7]3 years ago
5 0

Answer:

so fifteen gold coins is he buys one case

Step-by-step explanation:

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What can you say about the relationship between M and P? Which letter is the correct answer?
Dimas [21]

Answer:

Choice C is correct

Step-by-step explanation:

The first step is to re-write the equations in exponential form.

The first equation can be written as;

\frac{M}{N}=10^{4} since the base is 10 and 4 the exponent.

The second equation can be written as;

\frac{P}{N}=10^{5}

The second step is to make N the subject of the formula in both equations.

Solving for N from this equation \frac{M}{N}=10^{4}, yields;

N=\frac{M}{10^{4}}

Solving for N from the second equation \frac{P}{N}=10^{5}, yields;

N=\frac{P}{10^{5}}

Therefore;

\frac{M}{10^{4}}=\frac{P}{10^{5} }\\\\P=10M

6 0
3 years ago
Describe the slope of the line passing through points A(-2,3) and B(4,-3)
erik [133]

Answer:

0/2 is ZERO is positive

Step-by-step explanation:

6 0
3 years ago
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Pleas y'all help me with this
Fynjy0 [20]

Answer:

-\frac{26}{2}/  -\sqrt{9}/  13.5(percent)/ 0/ 13.5

Step-by-step explanation:

3 0
3 years ago
Which of the lines graphed in the diagram represents the equation 6x + 4y = 8
Blizzard [7]
In order to easily discern which graph is a proper representation of 6x + 4y = 8, you first need to convert the equation to y = mx+ b, also known as slope-intercept form. Here's how you can do this:
6x + 4y = 8
4y = -6x + 8
y = -1.5x + 2
The +2 tells you that your line will intercept the vertical y-axis at (0, 2). This narrows it down to graphs a and d. Then, because you have a NEGATIVE number in front of your x (it's -1.5), you can tell that your graph will be going down as it moves from left to right. This leaves you with graph d as your answer!
6 0
3 years ago
Read 2 more answers
A large corporation starts at time t = 0 to invest part of its receipts continuously at a rate of P dollars per year in a fund f
Andrews [41]

Answer:

A = \frac{P}{r}\left( e^{rt} -1 \right)

Step-by-step explanation:

This is <em>a separable differential equation</em>. Rearranging terms in the equation gives

                                                \frac{dA}{rA+P} = dt

Integration on both sides gives

                                            \int \frac{dA}{rA+P} = \int  dt

where c is a constant of integration.

The steps for solving the integral on the right hand side are presented below.

                               \int \frac{dA}{rA+P} = \begin{vmatrix} rA+P = m \implies rdA = dm\end{vmatrix} \\\\\phantom{\int \frac{dA}{rA+P} } = \int \frac{1}{m} \frac{1}{r} \, dm \\\\\phantom{\int \frac{dA}{rA+P} } = \frac{1}{r} \int \frac{1}{m} \, dm\\\\\phantom{\int \frac{dA}{rA+P} } = \frac{1}{r} \ln |m| + c \\\\&\phantom{\int \frac{dA}{rA+P} } = \frac{1}{r} \ln |rA+P| +c

Therefore,

                                        \frac{1}{r} \ln |rA+P| = t+c

Multiply both sides by r.

                               \ln |rA+P| = rt+c_1, \quad c_1 := rc

By taking exponents, we obtain

      e^{\ln |rA+P|} = e^{rt+c_1} \implies  |rA+P| = e^{rt} \cdot e^{c_1} rA+P = Ce^{rt}, \quad C:= \pm e^{c_1}

Isolate A.

                 rA+P = Ce^{rt} \implies rA = Ce^{rt} - P \implies A = \frac{C}{r}e^{rt} - \frac{P}{r}

Since A = 0  when t=0, we obtain an initial condition A(0) = 0.

We can use it to find the numeric value of the constant c.

Substituting 0 for A and t in the equation gives

                         0 = \frac{C}{r}e^{0} - \frac{P}{r} \implies \frac{P}{r} = \frac{C}{r} \implies C=P

Therefore, the solution of the given differential equation is

                                   A = \frac{P}{r}e^{rt} - \frac{P}{r} = \frac{P}{r}\left( e^{rt} -1 \right)

4 0
3 years ago
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