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3 years ago

U=10y/3xSolve for x

Mathematics

1 answer:

SSSSS [86.1K]3 years ago

4 0

Answer:

x=(3u)/(10y)

Step-by-step explanation:

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A city has a population of 310,000 people.Suppose that each year the population grows by 6.5% . What will the po

brilliants [131]

Answer:

546,397 people

Step-by-step explanation:

We solve for the above question, using the formula for Exponential growth

The formula is given as

P(t) = Po (1 + r)^t

Po = Initial population = 310,000

r = Exponential growth rate = 6.5% = 0.065

t = Time in years = 9

P(t) = Population size after time t

Hence:

P(t) = 310,000 × (1 + 0.065)⁹

P(t) = 546,396.82088 people

Approximately =546,397 people

The population will be 546,397 people after 9 years.

4 0

3 years ago

16,42 greatest common factor

kozerog [31]

2

42 ÷ 2 = 21
16 ÷ 2 = 8

Let's try the other factors of 42...

42 ÷ 6 = 7
16 ÷ 6 = 2.66
No...

42 ÷ 7 = 6
16 ÷ 7 = 2 2/7
No...

42 ÷ 14 = 3
16 ÷ 14 = 1.1428
No...

7 0

3 years ago

Which is the inverse of the function a(d)=5d-3? And use the definition of inverse functions to prove a(d) and a-1(d) are inverse

Drupady [299]

Answer:

$a'(d) = \frac{d}{5} + \frac{3}{5}$

$a(a'(d)) = a'(a(d)) = d$

Step-by-step explanation:

Given

$a(d) = 5d - 3$

Solving (a): Write as inverse function

$a(d) = 5d - 3$

Represent a(d) as y

$y = 5d - 3$

Swap positions of d and y

$d = 5y - 3$

Make y the subject

$5y = d + 3$

$y = \frac{d}{5} + \frac{3}{5}$

Replace y with a'(d)

$a'(d) = \frac{d}{5} + \frac{3}{5}$

Prove that a(d) and a'(d) are inverse functions

$a'(d) = \frac{d}{5} + \frac{3}{5}$ and $a(d) = 5d - 3$

To do this, we prove that:

$a(a'(d)) = a'(a(d)) = d$

Solving for $a(a'(d))$

$a(a'(d)) = a(\frac{d}{5} + \frac{3}{5})$

Substitute $\frac{d}{5} + \frac{3}{5}$ for d in $a(d) = 5d - 3$

$a(a'(d)) = 5(\frac{d}{5} + \frac{3}{5}) - 3$

$a(a'(d)) = \frac{5d}{5} + \frac{15}{5} - 3$

$a(a'(d)) = d + 3 - 3$

$a(a'(d)) = d$

Solving for: $a'(a(d))$

$a'(a(d)) = a'(5d - 3)$

Substitute 5d - 3 for d in $a'(d) = \frac{d}{5} + \frac{3}{5}$

$a'(a(d)) = \frac{5d - 3}{5} + \frac{3}{5}$

Add fractions

$a'(a(d)) = \frac{5d - 3+3}{5}$

$a'(a(d)) = \frac{5d}{5}$

$a'(a(d)) = d$

Hence:

$a(a'(d)) = a'(a(d)) = d$

7 0

3 years ago

Select all that apply. Which lines have a slope of -2? Line a line b line c line d

katrin2010 [14]

Do you have a photo of the options?

8 0

3 years ago

Read 2 more answers

Please help with solving

Makovka662 [10]

N.O = 4
N is midpoint of M.0
Meaning M.N also has to be 4
4+4= 8
N.P = 6
0.P = 2
8+ 2 = 10

4 0

2 years ago

U=10y/3xSolve for x​

U=10y/3xSolve for x