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astraxan [27]
3 years ago
10

Which of these is an example of physical change?

Chemistry
1 answer:
lana [24]3 years ago
6 0
A. Boiling water is an example of physical change, whereas digesting food, breaking glass, and shoveling snow are not.
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ASAP: in group 13, the only metalloid, boron, is at the very top of the group. Explain why the rest of the group has metallic be
Marrrta [24]

Electronegativity of boron is the highest in the group and it will form covalent bonds in all his combinations.

The rest of the group will form bonds with intermediate nature between covalent and ions bods in their respective compounds, with thallium (Tl) behaving most close to a metal.

Moreover boron have a very high melting points (around 2200 °C) while in the boron cristal the chemical bonds are directed in space, similar with carbon suggesting his nature as a non-metal.

Other elements form the group Al, Ga, In, Tl have lower melting points 660, 30, 157 and 304  °C, respectively. Also in the elemental state, they have metallic characteristics: metalic luster, ductility, high electrical and thermal conductivity.

3 0
3 years ago
Sodium chloride (NaCl) is commonly used to melt ice on roads during the winter. Calcium chloride (CaCl2) is sometimes used for t
mihalych1998 [28]

Answer:

\Delta Tfp_{NaCl}= -14.0\°C\\\\\Delta Tfp_{CaCl_2}=-11.1\°C

Explanation:

Hello!

In this case, since the freezing point depression caused by the addition of a solute, we use the following formula:

\Delta Tfp= i*m*Kfp

Thus, we first need to compute the molality of each solute, as shown below:

m_{NaCl}=\frac{220.g/(58.44g/mol)}{1.00kg} =3.76m\\\\m_{CaCl_2}=\frac{220.g/(110.98g/mol)}{1.00kg} =1.98m

Next, since NaCl has two ionic species, one Na⁺ and one Cl⁻, and CaCl₂ three, one Ca²⁺ and two Cl⁻, the van't Hoff's factors are 2 and 3 respectively, therefore the freezing point depressions turn out:

\Delta Tfp_{NaCl}= 2*3.76m*-1.86\°C/m=-14.0\°C\\\\\Delta Tfp_{CaCl_2}= 3*1.98m*-1.86\°C/m=-11.1\°C

It means that CaCl₂ is still better than NaCl because produces involves a higher melting point for the ice, so it would melt faster.

Best regards!

3 0
3 years ago
How can i find the number of electrons are gained or lost
wel

15. 1 were lost

16. 3 were gained

17. 2 were lost

18. 1 was gained

You can figure that out by looking at the number nest to the molecule with a  plus or minus sign next to it

+ = gained

- = lost

6 0
3 years ago
Free fire loveer...................​
rosijanka [135]

Answer:

Thanks! :) Have a great day!

Explanation:

5 0
3 years ago
0. A liquid solution of LiCl in water at 25°C contains 1 mol of LiCl and 7 mol of water. If 1 mol of LiCl⋅3H2O(s) is dissolved i
kupik [55]

Answer:

19.488 kJ

Explanation:

The overall reaction mechanism shows the reaction between LiCl and H₂O

LiCl.3H_2O ------> Li +\frac{1}{2} Cl_2+3H_2+\frac{3}{2} O_2     -------- (1)

2Li+Cl_2+10H_2O ----->LiCl.10H_2O              -------- (2)

3H_2+\frac{3}{2}O_2 -----> 3H_2O                                     --------- (3)

LiCl.7H_2O ------>  Li + \frac{1}{2} Cl_2+7H_20             ---------- (4)

The overall reaction =

LiCl.7H_2O +LiCl.3H_2O ------>  2LiCl.10H_2O

The heat effects of the above reactions from 1-4 respectively are in the order ; 11311.34 kJ, -857.49 kJ, -873.61 kJ and 439.288kJ respectively

The overall enthalpy change is:

\delta H = \delta H _{LiCl.3H_2O}+\delta H_{3H_2O}  + \delta  H_{2(LiCl.5H_2O)} + \delta  H _{liCl.7H_2O}

\delta H =Q at constant pressure;

Thus; Q = 1311.3 (kJ)  857.49 (kJ) -873.61 (kJ) + 439.288 (kJ)

Q = 19.488 kJ

Thus, the heat effect = 19.488 kJ after the addition of  1 mol of LiCl⋅3H2O(s)

4 0
3 years ago
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