Electronegativity of boron is the highest in the group and it will form covalent bonds in all his combinations.
The rest of the group will form bonds with intermediate nature between covalent and ions bods in their respective compounds, with thallium (Tl) behaving most close to a metal.
Moreover boron have a very high melting points (around 2200 °C) while in the boron cristal the chemical bonds are directed in space, similar with carbon suggesting his nature as a non-metal.
Other elements form the group Al, Ga, In, Tl have lower melting points 660, 30, 157 and 304 °C, respectively. Also in the elemental state, they have metallic characteristics: metalic luster, ductility, high electrical and thermal conductivity.
Answer:

Explanation:
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In this case, since the freezing point depression caused by the addition of a solute, we use the following formula:

Thus, we first need to compute the molality of each solute, as shown below:

Next, since NaCl has two ionic species, one Na⁺ and one Cl⁻, and CaCl₂ three, one Ca²⁺ and two Cl⁻, the van't Hoff's factors are 2 and 3 respectively, therefore the freezing point depressions turn out:

It means that CaCl₂ is still better than NaCl because produces involves a higher melting point for the ice, so it would melt faster.
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15. 1 were lost
16. 3 were gained
17. 2 were lost
18. 1 was gained
You can figure that out by looking at the number nest to the molecule with a plus or minus sign next to it
+ = gained
- = lost
Answer:
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Explanation:
Answer:
19.488 kJ
Explanation:
The overall reaction mechanism shows the reaction between LiCl and H₂O
-------- (1)
-------- (2)
--------- (3)
---------- (4)
The overall reaction =

The heat effects of the above reactions from 1-4 respectively are in the order ; 11311.34 kJ, -857.49 kJ, -873.61 kJ and 439.288kJ respectively
The overall enthalpy change is:

at constant pressure;
Thus; Q = 1311.3 (kJ) 857.49 (kJ) -873.61 (kJ) + 439.288 (kJ)
Q = 19.488 kJ
Thus, the heat effect = 19.488 kJ after the addition of 1 mol of LiCl⋅3H2O(s)