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sveticcg [70]
3 years ago
6

Photosynthesis is very important to us. Name 3 different types of ways you benefit from photosynthesis each day

Chemistry
1 answer:
Novay_Z [31]3 years ago
5 0
Breathing as photosynthesis releases oxygen
food as photosynthesis helps the plant to grow
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What will happen if you add more solute to a saturated solution?
Annette [7]
No more solute will dissolve at that temperature, the temperature would have to be increased in order for more solute to dissolve.
4 0
3 years ago
A solution of an acid could have a pH of __*<br> 3 to 5<br> 6 to 8<br> 9 to 11<br> 12 to 14
sdas [7]

Answer:

3 to 5

Explanation:

The pH scale is from 0 to 14.

Acids have a pH of anything less than 7.

Anything with a pH greater than 7 is considered to be a base.

If a solution has a pH of 7, it is neutral.

3 to 5 is in the range of less than 7, so a solution of an acid can have this pH.

6 to 8 includes less than 7 , 7 and greater than 7, so it is not just in the range of an acid.

9 to 11 and 12 to 14 are both in the range of greater than 7, so they have to be bases.

Therefore, the correct answer is 3 to 5.

4 0
3 years ago
If I have a 200 L container filled with nitrogen at a pressure of 1.0 atm, how many moles
egoroff_w [7]
Is it250 degrees c if so it would be <span> 4.66 moles</span>
6 0
3 years ago
Name the reaction type &amp; mechanism of the following reactions:
Natali5045456 [20]

Answer:

MECHANISM:

1) The lone pair on oxygen attacks the H-Br molecule forming a hydronium ion.

2) Formation of carbocation.

3) Attack of Nucleophile Br  −  .

Explanation:

4 0
3 years ago
Read 2 more answers
A sample contains 16 mg of polonium-218. After 12 minutes, the sample will contain 1.0 mg of polonium-218. What is the half life
mariarad [96]

Answer:

Half-life = 3 minutes

Explanation:

Using the radioactive decay equation we can solve for reaction constant, k. And by using:

K = ln2 / Half-life

We can find half-life of polonium-218

Radioactive decay:

Ln[A] = -kt + ln [A]₀

Where:

[A] could be taken as mass of polonium after t time: 1.0mg

k is Reaction constant, our incognite

t are 12 min

[A]₀ initial amount of polonium-218: 16mg

Ln[A] = -kt + ln [A]₀

Ln[1.0mg] = -k*12min + ln [16mg]

-2.7726 = - k*12min

k = 0.231min⁻¹

Half-life = ln 2 / 0.231min⁻¹

<h3>Half-life = 3 minutes</h3>

5 0
3 years ago
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