I think the more prevalent in the food we eat is Carbon-12 which is present in Most of the food we ingest. Both carbon-12 and carbon-14 are isotopes of carbon, they differ in the number of neutrons in each atom. Because of the different number of neutrons, carbon-12 and carbon-14 differ with respect to radioactivity. Carbon-12 is a stable isotope but carbon-14 undergoes radioactive decay.
There are 3 parts of the cell theory.
1. All living things are made up of cell- This <span>means that in order for something to be alive, it must either be a cell or made up of many cells. </span>
2. Cells are the smallest units (or most basic building blocks) of life- They are are the most fundamental units of a living organisms structure. They are also the basic units of function. This means that cells carry out all of the processes necessary for an organism to survive.
3. All cells come from preexisting cells through the process of cell division- This means that in order for a new cell to be created, it has to go through cell division with cells that already exist to become a new cell.
Hope this helps :)
Answer:
the enthalpy change for this reaction is -57.7 kJ/mol
Explanation:
Given:
HB₂O₃ = -1272.8 kJ/mol
HCOCl₂ = -218.8 kJ/mol
HBCl₃ = -403.8 kJ/mol
HCO₂ = -393.5 kJ/mol
Those are all standard enthalpies
Question: Calculate the enthalpy change for this reaction, ΔHreaction = ?
The enthalpy of the reaction is calculated using the standard enthalpies of formation of both products and reagents. To understand better, the reaction is as follows
B₂O₃ + 3COCl₂ → 2BCl₃ + 3CO₂
Where the compounds on the left are the reactants and the compounds on the right are the products
ΔHreaction = ∑ΔHproducts - ∑ΔHreactants
![delta(H)_{reaction} =((2*(-403.2)+(3*(-393.5))-((1*(-1272.8)+(3*(-218.8))=-57.7kJ/mol](https://tex.z-dn.net/?f=delta%28H%29_%7Breaction%7D%20%3D%28%282%2A%28-403.2%29%2B%283%2A%28-393.5%29%29-%28%281%2A%28-1272.8%29%2B%283%2A%28-218.8%29%29%3D-57.7kJ%2Fmol)
Please be careful with the signs.
Answer:
1.41 moles H2O2(with sig figs)
Explanation:
okay so what is the molar mass of H2O2= (1.008 g/mol)2+(16.00g/mol)2= (2.016+ 32.00) g/ mol
= 34. 02 g/mol
48.0g H2O2* 1 mol H2O2/ 34.02 g H2O2= 1.41 mol H2O2
In order to perform the experiment, in identifying the
temperature of different kinds of liquid freeze—the needed equipment is the
thermometer. It is because the thermometer is an equipment that helps in
determining a temperature. The variable in the experiment would be the
temperature as this is not consistent for the effects or outcome will likely
change.