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djyliett [7]
3 years ago
15

If you were to deposit 2000 in an account that earns simple interest of 3.5% per year, how much would the account be worth in 50

years
Mathematics
1 answer:
Deffense [45]3 years ago
5 0

Answer:the interest would be $3,500

Step-by-step explanation:  you have to multiply all of the numbers together but change the 3.5% to a decimal of 0.035

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Delicious77 [7]
If said number is x, that means that twice (2 times) a number and 2x-7=13. Adding 7 to both sides, we get 2x=20 and by dividing both sides by 2 we get x=10. For 2, we see that the sum of a number and 6 is first priority, so we have (x+6)*7=-43. Dividing both sides by 7, we get x+6=-43/7. After that, we subtract both sides by 6 to get -43/7-6=x
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3 years ago
The school's math team has 14 new members this year, which makes a total of 34. The number of new members represents what percen
Aleksandr-060686 [28]
To find a % you want to divide the # of new members, by the total # of members.

14/34 =0.41

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6 0
4 years ago
Read 2 more answers
Does each equation represent exponential decay or exponential growth?
agasfer [191]

An exponential equation is represented as: \mathbf{y = ab^x}, where b represents rate

  • Exponential growth: \mathbf{y = 5(7)^x},  \mathbf{y = 3(4.2)^x} and \mathbf{y = 0.6(1.3)^x}
  • Exponential decay: \mathbf{k = 4.2(0.28)^x}
  • Neither: \mathbf{h(x) - 3x + 1.3}

An exponential equation is said to represent growth, if the rate is greater than 1, while it represents decay if the rate is less than 1.

This means that:

\mathbf{y = 5(7)^x},  \mathbf{y = 3(4.2)^x} and \mathbf{y = 0.6(1.3)^x} represent exponential growth because 5, 4.2 and 1.3 are greater than 1

Also,

\mathbf{k = 4.2(0.28)^x} represents exponential decay because 0.28 is less than 1

While

\mathbf{h(x) - 3x + 1.3} is not an exponential function

Read more about exponential functions at:

brainly.com/question/11487261

5 0
2 years ago
X 0 1 2<br> y -4 -2 0<br> what is the constant rate?
Juliette [100K]

Answer:

+ 2

Step-by-step explanation:

x | y

0 | -4

1 | -2

2 | 0

You are adding 2 to y every time you have a new x.

5 0
3 years ago
Right Triangle Trig.
d1i1m1o1n [39]

The values are vx = \frac{14\sqrt{3} }{\sqrt{2} }, vw = \frac{14\sqrt{3} }{\sqrt{2} } and m∠x = 45°, for the given right angle diagram.

Step-by-step explanation:

The given is,

                Right angled triangle XVW,

                                     XW = 14\sqrt{3}

                                   m∠V = 90°

                                  m∠W = 45°

Step:1

              Given diagram is right angle triangle,

              Trigonometric ratios for right angle is,

                                 sin ∅ =\frac{Opp}{Hyp}............................(1)

                                  cos ∅ = \frac{Adj}{Hyp} .........................(2)

                                  tan ∅ = \frac{Opp}{Hyp}..........................(3)

Step:2

             For the value of VX,

                                   sin ∅ =\frac{VX}{XW}

            From given,

                               ∅ = 45°

                           XW = 14\sqrt{3}

           Above equation becomes,

                                     sin 45 =\frac{VX}{14\sqrt{3} }

            Where, Sin 45 = \frac{1}{\sqrt{2} },

                                            \frac{1}{\sqrt{2} } = \frac{VX}{14\sqrt{3} }

                                           VX = \frac{14\sqrt{3} }{\sqrt{2} }

Step:3

              For the value of VW,

                                   cos ∅ =\frac{VW}{XW}

            From given,

                               ∅ = 45°

                           XW = 14\sqrt{3}

           Above equation becomes,

                                     cos 45 =\frac{VW}{14\sqrt{3} }

            Where, cos 45 = \frac{1}{\sqrt{2} },

                                            \frac{1}{\sqrt{2} } = \frac{VW}{14\sqrt{3} }

                                           VW = \frac{14\sqrt{3} }{\sqrt{2} }

Step:4

             For the value m∠x = a,

                                      tan a =\frac{VX}{VW}

            From given,

                            VX = \frac{14\sqrt{3} }{\sqrt{2} }

                           VW = \frac{14\sqrt{3} }{\sqrt{2} }

           Above equation becomes,

                                     tan a =\frac{\frac{14\sqrt{3} }{\sqrt{2} } }           {\frac{14\sqrt{3} }{\sqrt{2} } }

                                      tan a = 1

                                             a = tan^{-1} (1)

                                             a = 45°

                                 m∠x = a = 45°

Step:5

            Check for solution,

                         m∠v  = m∠w + m∠x

                                   = 45° + 45°

                            90° =   90°

Result:

            The values are vx = \frac{14\sqrt{3} }{\sqrt{2} }, vw = \frac{14\sqrt{3} }{\sqrt{2} } and m∠x = 45°, for the given right angle diagram.

           

5 0
4 years ago
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