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kondaur [170]
3 years ago
6

An advantage of parallel circuits is that they A) stop transmitting all current if even one resistor breaks. B) form a single pa

th through which the current flows. C) allow current to flow even if some paths are cut. D) divide the voltage evenly between all resistors.
Physics
2 answers:
gizmo_the_mogwai [7]3 years ago
5 0

Answer: C) allow current to flow even if some paths are cut.

Explanation:

In parallel circuit, the components are arranged in parallel paths across the same potential difference. The overall resistance decreases in parallel circuit. Different amount of current flows in different paths according to the resistance offered by the components. The main advantage of the parallel circuit is even if one component fuses, it does not effect other components. Thus, the current flows in the other paths even if one path disconnects.

svetoff [14.1K]3 years ago
4 0

Parallel circuits allow current to flow even if some paths are cut, because a parallel circuit has more than one current-carrying path through it.

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A calculator has a resistance of 22 Ω. What is the power rating for this calculator when connected to a 1.5 V battery?
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Answer:

33

Explanation:

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In order for electricity from a battery to power a light bulb, the wire has to provide the electricity a path to do what?
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Answer:

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You travel 60 meters to the left in 20 seconds and then you travel 60 meters to the right in 30 seconds; what is your average ve
vovikov84 [41]
Average velocity = displacement / time

In this case, since you move left 60, then right 60, you return to the starting point making the displacement zero.

average velocity = 0 / 60 sec = zero

the average speed is calculated using total distance traveled.

average speed = distance / time

average speed = 120 meters / 60 sec = 2 m/s
4 0
3 years ago
Determine the kinetic energy of the ball immediately after it is hit. (You must provide an answer before moving to the next part
earnstyle [38]

The question is incomplete. Here is the complete question.

A baseball palyer hits a 5.1 oz baseball with an initial velocity of 140ft/sat an angle of 40° with the horizontal as shown. Determine

a) The kinetic energy of the ball immediately after it is hit

b) The kinetic energy of the ball when it reaches its maximum height

c) The maximum height above the ground reached by the ball.

Answer: a) KE = 131.64 J

              b) KE = 0

              c) h = 126 ft

Explanation: <u>Kinetic</u> <u>energy</u> is the energy an object posses due to its motion. It can be calculated as KE=\frac{1}{2}mv^{2}

a) Kinetic energy's unit is Joule. So, we have to transform ounce in kg and ft/s in m/s for the units to correspond:

m = 5.1(0.02835)

m = 0.1445 kg

v = 140 ft = 42.67 m/s

Then, kinetic energy is

KE=\frac{1}{2}(0.1445)(42.67)^{2}

KE = 131.64 J

Kinetic energy immediately after the ball is hit is 131.64 J.

b) At its maximum height, the ball has its highest potential energy. Because of the law of conservation of energy, when potential energy is maximum, kinetic energy is minimum and vice-versa. So, at the maximum height, kinetic energy is 0.

c) This type of motion is <u>projectile</u> <u>motion</u>. The maximum height on a projectile motion can be determined by

v_{y}^{2}=v_{0y}^{2}-2g\Delta y

When h is maximum, v_{y}=0

Velocity of the ball has an angle with the horizontal, so initial velocity at the y-axis is

v_{0y}=v_{0}sin(\theta)

Substituting and solving

v_{y}^{2}=v_{0}^{2}sin^{2}(\theta)-2gh

0=(42.67)^{2}sin^{2}(40)-2(9.8)h

19.6h=(42.67)^{2}(0.643)^{2}

h=\frac{(1820.73)(0.4132)}{19.6}

h = 38.4 m

Transforming into ft: h = 126 ft

The maximum height above the ground reached by hte ball is 126 feet.

6 0
3 years ago
In our lab experiment on Ohm's law, the power supply is connected to a circuit containing one resistor, and a direct current of
lapo4ka [179]

Answer: (A) 3.0=A

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Besides, we have to consider the resitance equivalent for a parallel connection. This is given by:

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If we connect the same resistance, the equivalent resistance is R/2.

Initlally  the current is 1.5 A when one resistance is connected to the batttery. When a second resistance with the same value is connected in parallel to the battery, we have V=Re*Ifinal= (R/2)*Ifinal

also we know that V=R*Iinitial so Iinitial=V/R

then Ifinal= 2*V/R=2*Iinitial

3 0
4 years ago
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